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3 years ago

Please answer correctly!! Will mark brainliest!!!

Mathematics

2 answers:

ki77a [65]3 years ago

8 0

Answer:

Step-by-step explanation:

<h2>YOU WILL DO GREAT</h2>

34kurt3 years ago

8 0

Answer:

$\frac{1}{a^{12}b^8}$

Step-by-step explanation:

Considering the expression:

$\left(\frac{a^{-3}}{b^2}\right)^4$

$\frac{\left(a^{-3}\right)^4}{\left(b^2\right)^4}$

Now state the property:

$a^{-1}=\frac{1}{a^n}, a\neq 0$

$\frac{\frac{1}{a^{12}}}{\left(b^2\right)^4}$

$\frac{\frac{1}{a^{12}}}{b^8}$

$\frac{1}{a^{12}b^8}$

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PLEASE HELP, AND PLAESE EXPLAIN!!!

tankabanditka [31]

Answer:

D. 22.5 sq. un.

Step-by-step explanation:

W divides BU so that there is a ratio of 1;2 meaning that there are 3 parts.

That means that 3 parts is BUV; we know that one of those parts is 4.5 sq. un. so 4.5*3=13.5 sq. un. - Also 4.5*2=9 to get WUV

V is the midpoint of the line BS so that means that BUV and UVS are equal

we know that BUV is 13.5 so we multiply that by 2 to get the whole triangle

=27

The last step is to get rid of BVW which we know is 4.5

27-4.5=22.5

7 0

2 years ago

HELLO GUYS!!

Kipish [7]

The Area of the lawn is:

20m x 14m = 280m^2

The Area of the Circle is:

pi x 5^2 = 78.54

280 - 78.54 = 201.46m^2

8 0

2 years ago

Read 2 more answers

I need to increase my sales by 35% this month I’m currently at 45 sales how many sales do I need to meet my goal ?

telo118 [61]

Assume that 100% = 45 sales and 35% = X sales amount

You can create a ratio to help you solve for x

45 = 100%
x = 35 %

Which is equal to this fraction: (45/x) = (100/35)

Solving for X by cross multiplying and dividing by 100:
[(45)(35)] / 100 = X = 15.75 = 16 sales (rounded up)

You would need at least 16 sales to increase sales total by 35%

8 0

3 years ago

Read 2 more answers

if anyone is willing to help me with my math homework I have 8 worksheets I need to get finished by tommorow if anyone is willin

Svetradugi [14.3K]

It depends what kind of math it is. Fractions, angles, or something else. I don’t want to give you wrong answers.

5 0

3 years ago

Read 2 more answers

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago