Answer:
8.2763 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that the acid dissociation constant = 3.5×10⁻⁸
pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46
Given concentration of acid = [acid] = 0.244 M
pH = 6.733
So,
6.733 = 7.46+log[base]/0.244
[Base] = 0.0457 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0457 × 2 = 0.0914 moles
Molar mass of potassium hypochlorite = 90.55 g/mol
Mass = Moles × Molar mass = (0.0914 × 90.55) g = <u>8.2763 g</u>
Br₂ + FeBr₃----->Br-Br-FeBr₃
In this reaction, FeBr₃, is a electron-deficient species that is it act as a lewis acid.
While Br₂, donates its electron to FeBr₃.
Br₂, act as a electrophile while FeBr₃ is a lewis acid.
Futher if Br₂, undergoes a reaction an aromatic ring , then that ring will attack Br₂, and it acts as a electrophile.
Answer:
residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.
filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue
Explanation:
Answer:
5.31x10⁻⁶ C
Explanation:
The cube is located 100 m altitude from the ground, so the superior face is at 100m and has E = 70 N/C, and the inferior face is at the ground with E = 130 N/C.
The electric field is perpendicular to the bottom and the top of the cube, so the total flux is the flux at the superior face plus the flux at the inferior face:
Фtotal = Ф100m + Фground
Where Ф = E*A*cos(α). α is the angle between the area vector and the field (180° at the topo and 0° at the bottom):
Фtotal = E100*A*cos(180°) + Eground*A*cos(0°)
Фtotal = 70A*(-1) + 130*A*1
Фtotal = 60A
By Gauss' Law, the flux is:
Фtotal = q/ε, where q is the charge, and ε is the permittivity constant in vacuum = 8.854x10⁻¹² C²/N.m²
A = 100mx100m = 10000 m²
q = 60*10000*8.854x10⁻¹²
q = 5.31x10⁻⁶ C
Answer:
[Co(H₂O)₆]²⁺ = 0.361 M
Explanation:
[CoCl₂ . 6H₂O] + 2Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[Co(H₂O)₆]²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[CoCl₄]²⁻ = 0.361 M ∴ [Co(H₂O)₆]²⁺ = 0.361 M
The equation shows that the concentration of [Co(H₂O)₆]²⁺ should be equal to the concentration of [CoCl₄]²⁻.
