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Murrr4er [49]
3 years ago
13

Example of obtuse angle​

Chemistry
1 answer:
marishachu [46]3 years ago
8 0

Answer:

when the degree is less than 90

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The standard free energy change for a reaction in an electrolytic cell is always:_________
sattari [20]

Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.

Explanation:

Electrolytic cells use electric currents to drive a non-spontaneous reaction forward.

Relation of standard free energy change and emf of cell

\Delta G^o=-nFE^0_{cell}

where,

\Delta G^o = standard free energy change

  n= no of electrons gained or lost

F= faraday's constant

E^0_{cell} = standard emf

E^0_{cell}   = standard emf = -ve  , for non spontaneous reaction

Thus  \Delta G^o=(-ve)(-ve)=+ve

Thus standard free energy change for a reaction in an electrolytic cell is always positive.

8 0
3 years ago
How many kJ are 3,340J?
forsale [732]
The answer I believe is 3.340kj.
8 0
3 years ago
Which of the following on the periodic table corresponds to a principal energy level?
kolbaska11 [484]

Answer:

representative elements

5 0
3 years ago
Read 2 more answers
An atom has 11 protons, 10 electrons and 13 neutrons. What is the<br> charge for this atom?
Aliun [14]

Answer:

<h3>the charge is +1 </h3>

Explanation:

<h3>as we know nutral atom have equal number of protons and electrons</h3><h3>from the give this element have 11 protons so if it is nutral it must have 11 electrons,but in the question this atom is charged this means it gains or losts certain amount of electrons , this atom has 11 proton and 10 electron from this we can understand this atom dicreases by 1 from its proton, this means it losts one electron .</h3><h3>when an atom lostes electron it's charge become positive with the number of electrons it lostes .</h3><h3>this atom lost 1 electron there fore it have +1 charge and become ion called cathion</h3>

3 0
2 years ago
Use the following information to answer the following question.
Irina-Kira [14]

Answer:

For these problems, we need to compare the theoretical yield that we'd get from performing stoichiometry to the actual yield stated in the problem. % yield is the actual yield/theoretical yield x 100%  

Cu + 2 AgNO₠→ Cu(NOâ‚)â‚‚ + 2 Ag ==> each mole of copper yields two moles of silver  

12.7-g Cu x ( 1 mol Cu /63.5-g Cu) x ( 2 mol Ag / 1 mol Cu) x (108-g Ag / 1 mol Ag) = 43.2-g Ag. This is the theoretical yield. Now, since we got 38.1-g Ag our % yield is:  

38.1-g/43.2-g x 100% = 88.2%

Explanation:

5 0
2 years ago
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