$n;\ n+1;\ n+2;\ n+3;\ n+4-five\ consecutive\ integers\\\\(n)+(n+1)+(n+2)+(n+3)+(n+4)=195\\n+n+1+n+2+n+3+n+4=195\\5n+10=195\ \ \ \ \ |subtract\ 10\ from\ both\ sides\\5n=185\ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\n=37\\\\Answer:\boxed{37;\ 38;\ 39;\ 40;\ 41}$

7 0

3 years ago

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Malcolm has been watching a roulette-style game at a local charity bazaar. The game has only ten numbers on the wheel, and every

Mariana [72]

Answer:

Malcolm is showing evidence of gambler's fallacy.

This is the tendency to think previous results can affect future performance of an event that is fundamentally random.

Step-by-step explanation:

Since each round of the roulette-style game is independent of each other. The probability that 8 will come up at any time remains the same, equal to the probability of each number from 1 to 10 coming up. That it has not come up in the last 15 minutes does not increase or decrease the probability that it would come up afterwards.

5 0

3 years ago