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Strike441 [17]
2 years ago
11

Three different sets of objects contain 2, 3, and 14 objects, respectively. How

Mathematics
2 answers:
RoseWind [281]2 years ago
7 0

Answer:

C) 84

Step-by-step explanation:

Use the Fundamental Counting Principle, which states that if there are p ways to do one thing, and q ways to do another thing, then there are p×q ways to do both things. In this case, we have 2 ways to select one object from the first set, 3 ways to select one object from the second set, and 14 ways to select one object from the third set. So, we multiply and do 2*3*14=84

Therefore, there are 84 unique combinations

svet-max [94.6K]2 years ago
5 0
The answer is C, eighty four combinations
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Step-by-step explanation:

Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.

<em>A segment XD is drawn in rectangle QUAD as shown  below. </em>

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