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3 years ago

11

Three different sets of objects contain 2, 3, and 14 objects, respectively. How

2 answers:

RoseWind [281]3 years ago

7 0

Answer:

C) 84

Step-by-step explanation:

Use the Fundamental Counting Principle, which states that if there are p ways to do one thing, and q ways to do another thing, then there are p×q ways to do both things. In this case, we have 2 ways to select one object from the first set, 3 ways to select one object from the second set, and 14 ways to select one object from the third set. So, we multiply and do 2*3*14=84

Therefore, there are 84 unique combinations

svet-max [94.6K]3 years ago

5 0

The answer is C, eighty four combinations

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andrey2020 [161]

Answer:

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Step-by-step explanation:

If we find the diameter, we can find the radius by halving the diameter.

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The distance formula will give us the length between (3,1) and (9,9).

The distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

The distance between the $x$ 's is 9-3=6.

The distance between the $y$ 's is 9-1=8.

The distance between the points is given by $\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10$ .

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3 years ago

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olga_2 [115]

Answer:

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Step-by-step explanation:

The given equation is:

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Answer:

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