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ryzh [129]
3 years ago
5

How do you add fractions

Mathematics
2 answers:
vichka [17]3 years ago
7 0
2 3 5. 1 - + - = - simplified = - 5x2 2x5. 10. 2
Paul [167]3 years ago
3 0

all you do is find a common denominator and then add numerator to numerator and denominator to denominator
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192h

Step-by-step explanation:

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Explain me PLEASEEEE!!!
kirza4 [7]

Answer:

\frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

Step-by-step explanation:

Let us revise the properties of exponents

  • a^{m}.a^{n}=a^{m+n}
  • \frac{a^{m}}{a^{n}}=a^{m-n}
  • (a^{m})^{n}=a^{m.n}
  • a^{-m}=\frac{1}{a^{m} }

Let us use these properties to solve the question

→ By using the 3rd property above

∵ (a^{2})^{3}=a^{2.3}=a^{6}

∴ \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10} }

→ By using the 1st property above

∵ a^{6}.a^{-3}=a^{6+-3}=a^{6-3}=a^{3}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}

→ By using the 2nd property above

∵ \frac{a^{3}}{a^{10}}=a^{3-10}=a^{-7}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}

→ By using the 4th property above

∵ a^{-7}=\frac{1}{a^{7}}

∴  \frac{(a^{2})^{3}.a^{-3}}{a^{10}}=\frac{a^{6}.a^{-3}}{a^{10}}=\frac{a^{3}}{a^{10}}=a^{-7}=\frac{1}{a^{7}}

8 0
3 years ago
Factor and find the x-intercepts f(x) = x^2– 3x - 4
velikii [3]

Answer:

see explanation

Step-by-step explanation:

To find the x- intercepts let f(x) = 0, that is

x² - 3x - 4 = 0

Consider the factors of the constant term (- 4) which sum to give the coefficient of the x- term (- 3)

The factors are - 4 and + 1, since

- 4 × 1 = - 4 and - 4 + 1 = - 3, thus

(x - 4)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 1 = 0 ⇒ x = - 1

x- intercepts are (- 1, 0 ) and (4, 0 )

6 0
3 years ago
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