Answer:
The answer to your question is 27 g of Al
Explanation:
Data
mass of Al = ?
moles of Al₂O₃ = 0.5
The correct formula for the product is Al₂O₃
Balanced chemical reaction
4Al + 3O₂ ⇒ 2Al₂O₃
Process
1.- Calculate the molar mass of the product
Al₂O₃ = (27 x 2) + (16 x 3)
= 54 + 48
= 102 g
2.- Convert the moles of Al₂O₃ to grams
102 g ---------------- 1 mol
x ---------------- 0.5 moles
x = (0.5 x 102) / 1
x = 51 g of Al₂O₃
3.- Use proportions to calculate the mass of Al
4(27) g of Al --------------- 2(102) g of Al₂O₃
x --------------- 51 g
x = (51 x 4(27)) / 2(102)
x = 5508 / 204
x = 27 g of Al
1. element
2. compound
3. element
4. compound
5. compound
6. compound
basically, if its on the periodic table, its an element. for example, rock can be made of many things in the periodic table, therefore its a compound. salt, is NaCl, which are two elements put together, therefore its a compound.
If a negatively charged ion is more concentrated inside the cell, the forces required to balance the chemical gradient would be directed <u>Inward</u>. Thus, the equilibrium potential for this ion would be <u>Positively</u> charged.
<u>Explanation:</u>
The measurement of potential of resting membrane is distributed unequally in the form of ions or the charged particles, which are consist between both the cell's internal structure and external structure, by the membrane's changing permeability to various ion forms.
Like in most of the neurons the potassium and organic ions which are common in amino acids are present more in internal portion of cell than its outer portion. By comparison sodium and chloride ions are normally present in the cell externally at higher concentrations. This implies there are balanced gradients of concentration around the membrane for all the most concentrated forms of ions.
Answer:
2.39 atm
Explanation:
We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:
Mass of Ne = 0.41 g
Molar mass of Ne = 20 g/mol
Mole of Ne =.?
Mole = mass / molar mass
Mole of Ne = 0.41 / 20
Mole of Ne = 0.0205 mole
Next we shall convert 200 mL to L.
1000 mL = 1 L
Therefore,
200 mL = 200 mL × 1 L / 1000 mL
200 mL = 0.2 L
Next, we shall convert 11 °C to Kelvin temperature.
T(K) = T(°C) + 273
T(°C) = 11 °C
T(K) = 11 + 273
T (K) = 284 K
Finally, we shall determine the pressure. This can be obtained as follow:
Mole of Ne (n) = 0.0205 mole
Volume (V) = 0.2 L
Temperature (T) = 284 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
PV = nRT
P × 0.2 = 0.0205 × 0.0821 × 284
P × 0.2 = 0.4779862
Divide both side by 0.2
P = 0.4779862 / 0.2
P = 2.49 atm
Therefore, the pressure of the gas is 2.39 atm
