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mash [69]
4 years ago
10

What type of molecular attraction accounts for the high boiling point of H2O

Chemistry
1 answer:
aleksklad [387]4 years ago
3 0

Hydrogen bonding

Explanation:

Hydrogen bonding between water molecules account for its high boiling point.

  • Intermolecular forces determines the bulk of the physical properties of matter.
  • Hydrogen bond is a special type of dipole dipole attraction
  • It forms when a hydrogen on one molecule attracts an electronegative atom on another usually Oxygen, fluorine and nitrogen.
  • These intermolecular forces are very strong and difficult to break.

Learn more:

Hydrogen bond brainly.com/question/10602513

#learnwithbrainly

You might be interested in
If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days?
Crank

Answer: 625 grams

Explanation:

14 goes into 56, 4 times.

10,000÷2=5,000 - first half life

5,000÷2=2,500 - second half life

2,500÷2=1,250 - 3rd half life

1,250÷2= 625 - 4th half life

Note: don't type "grams" after 625, just type "625".

5 0
2 years ago
Determine the primary means of melting that would occur at divergent boundaries, convergent boundaries, and within a plate (intr
Schach [20]

By determining the primary means of melting that would occur at divergent boundaries and the appropriate labels to the respective Convergent plate boundary.

What is the Convergent plate boundary?

As the plate delves deeper into the convergent boundary, pressure and temperature rise along with it. When the pore water is released, this contributes to partial melting.

As a result, when the situation is at the melting curve, a rise in temperature will result in a large partial melt because of the presence of water. As seen in the wet peridotite melting curves in the aforementioned curves.

Only the peridotite's temperature changes during intraplate melting, not the pressure. Therefore, as the temperature rises, it will begin to melt.

Decompression causes melting at diverging boundaries. Temperature plays no part in this. As the plate delves deeper into the convergent boundary, pressure and temperature rise along with it.

When the pore water is released, this contributes to partial melting. As a result, when the situation is at the melting curve, a rise in temperature will result in a large partial melt because of the presence of water. As seen in the wet peridotite melting curves in the aforementioned curves.

Only the peridotite's temperature changes during intraplate melting, not the pressure. Therefore, as the temperature rises, it will begin to melt Decompression causes melting at diverging boundaries. Temperature plays no part in this.

Hence, the answer is Convergent plate boundary

Learn more about Convergent plate boundary,

brainly.com/question/21683926

# SPJ4

8 0
2 years ago
A sample of gas occupies 10 L at STP. What
puteri [66]

Pressure is 5.7 atm

<u>Explanation:</u>

P1 = Standard pressure = 1 atm

P2 = ?  

V1 = Volume = 10L

V2= 2.4L

T1 = 0°C + 273 K = 273 K

T2 = 100°C + 273 K = 373 K

We have to find the pressure of the gas, by using the gas formula as,

$\frac{P 1 V 1}{T 1}=\frac{P 2 V 2}{T 2}

P2 can be found by rewriting the above expression as,

$P 2=\frac{P 1 \times V 1 \times T 2}{T 1 \times V 2}

Plugin the above values as,

$P 2=\frac{1 \text {atm} \times 10 L \times 373 \mathrm{K}}{273 \mathrm{K} \times 2.4 \mathrm{L}}=5.7 \text { atm }

4 0
3 years ago
In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?
WINSTONCH [101]

Answer : The reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

Explanation :

Conjugate acid : A species that is formed by receiving of a proton (H^+) by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3

In this reaction, CH_3COO^-(base) react with NH_4^(acid) to give CH_3COOH(conjugate acid) and NH_3(conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

8 0
3 years ago
If the E°cell value = +0.46V and E°(Ag+/Ag) = +0.80V
fenix001 [56]

Answer:

0.34

Explanation:

Cu>>>Cu2+(oxidation number increases)[Oxidation occurs]

Ag+>>>Ag(Oxidation number decreases) [Reduction occurs]

E°=0.80-0.46

=0.34V

8 0
2 years ago
Read 2 more answers
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