Which climate zone is most affected by its altitude?

The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points

just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

$\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

Input the value :

P₂ = P₁V₁/V₂

P₂ = 2 x 200 / 10

P₂ = 40 atm

3 0

3 years ago

Imagine an alternate universe where the value of the Planck constant is 6.6207 x 10^-36 J*s.

hoa [83]

Answer:

See explanation

Explanation:

According to Louis de Broglie, particles could exhibit wavelike properties and have an associated wavelength.

Now for a turtle with a mass of 450. g, 29. cm long, moving at 2.7 cm/s, recall that we can only describe a by quantum mechanics when the body is very small and its associated wavelength is large.

This object has a large mass, hence it is discussed by classical rather than quantum mechanics

4 0

3 years ago

Chemistry chemistry chemistry chemistry chemistry chemistry

fgiga [73]

Explanation:

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8 0

3 years ago

Read 2 more answers

WILL GIVE BRAINIEST IF HELP Which of these is a compound

NikAS [45]

b the awnser is b its a compound of carbon C and 2 oxygon atoms O sub 2

5 0

3 years ago

How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)

Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g$

To calculate the heat absorbed by the water, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(100-25)^oC=75^oC$

Putting values in above equation, we get:

$q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ$

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0

3 years ago