According to the formula of vapor pressure:
Pv(solu) = n P°v(water)
when we have Pv(solu) = 23.1 torr & Pv(water) = 23.8 torr so we can get the mole fraction of water (n)
∴ n = Pv(solu) / Pv(water)
= 23.1 / 23.8 = 0.97 mol
when mole fraction of water = moles of water / (moles of water + moles of glucose)
So by substitution::
0.97 = 27.78 / (27.78+ X)
∴moles of gulcose = 0.85 mol
∴ mass of glucose = no.of moles * molar mass
= 0.85 * 180 = 152 g
Each scientist could be working on the problem for different reason. Or, each scientist could be focused on different elements of the problem, concluding in different conclusions between the scientist.
Answer:
-142.3 per mole, b) 2 O₃ (g)
Explanation:
2O₃ (g) → 3O₂ (g) ΔH = -284.6 KJ
According to the equation 2 mole of ozone yields 3 mole of oxygen gas and the enthalpy change = -284.6 KJ
a) enthalpy change per mole = -284.6 / 2 mole = -142.3 KJ per mole
b) The reaction is exothermic since the enthalpy change is negative meaning that the heat of reactant is greater than heat of product. If the heat of product is greater than heat of reactant meaning enthalpy change is positive; the reaction is endothermic. 2 O₃ (g) has higher enthalpy compared to 3 O₂ (g) since the enthalpy change is negative
The laboratory aid that is used to transfer liquid from a wide-mouth container to a small-mouth container is the funnel. It is shaped like an inverted cone, with an extension of a small tube where the liquid passes. The filter paper is shaped into a cone and inserted to the funnel. The funnel allows you to transfer the liquid without spilling. In filtration, you separate the solid precipitate from the liquid filtrate. It depends on you which one of these you would keep. If you want to keep the filtrate, then the funnel is an efficient way to use if you don't want any of the filtrate to go to waste.