Answer:
f. 0.0537 kg
Explanation:
To solve this, we use the formula for force of buoyancy (Fb) = Vs × D × g
Where; Fb= Force of buoyancy
Vs= Volume of submerged
block
D= Density of water that block
submerges in
g= acceleration due to gravity
In this question, volume of block can be calculated using L×B×H
= 4.3cm × 5.9cm × 2.75cm = 69.7675cm^3
If 77% of the block is submerged in water, then 77/100 × 69.7675cm^3
= 53.72cm^3 is the Volume of submerged block
Density of water is known as 1000kg/m^3 while the gravitational force is 10m/s^2
We need to convert the Vs (volume of submerged block) to m^3 by dividing by 1,000,000
Hence, Vs = 53.72/1000000
Vs= 0.00005372m^3
Using the formula; (Fb) = Vs × D × g
Fb = 0.00005372m^3 × 1000kg/m^3 × 10m/s^2
Fb = 0.5372kg/m/s^2
Therefore, the force of buoyancy of the object on water is 0.5372kg/m/s^2
Recall that; Mass (m) = Volume (V) × Density (D)
Force of buoyancy (Fb) = Vs×D = mass (m) × acceleration due to gravity (g)
i.e. mass = Fb/g
= Mass of the block = 0.5372/10
Mass = 0.05372kg
Therefore, the mass of the block in kg is 0.05372kg
