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AVprozaik [17]
3 years ago
15

A table costs $50 more than a chair. The cost of 6 chairs and 1 table is $750. The equation 6x + x + 50 = 750, where x is the co

st of one chair, represents this situation. Plug in the values from the set {50, 100, 150} to find the correct value of x.
The value of x that makes the equation true is(50,100,or 150) So, the cost of a chair is($50,$100,or $150)
and the cost of a table is ($50,$100,or $150)

Please tell me the three answers. The options are all listed above for the value of x, the cost of a chair, and the cost of a table.
Mathematics
2 answers:
Pavel [41]3 years ago
5 0

Answer:

the answer would be

100

100

50

Varvara68 [4.7K]3 years ago
4 0
The equation representing the cost of 6 chairs and a table is:

6x + x + 50 = 750

⇒
7x = 700

This equation is true for x = 100 because:

7(100) = 700

So, the cost of one chair will be $100.

Cost of table is $50 more than a chair, so the cost of one table is $150.

So the answers are:
$ 100
$ 100
$ 150
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Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

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