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Kipish [7]
3 years ago
6

A 100-g aluminum calorimeter contains 500 g of water at a temperature of 20ºC. Then a 140-g piece of metal, initially at 344ºC,

is added to the calorimeter. The metal, water, and calorimeter reach an equilibrium temperature of 32ºC. What is the specific heat capacity of the metal? The specific heat capacity of aluminum is 910 J/kg ∙ K, and of water is 4190 J/kg ∙ K.
580 J/kg ∙ K
495 J/kg ∙ K
601 J/kg ∙ K
228 J/kg ∙ K
Physics
1 answer:
Lunna [17]3 years ago
3 0
601 J/kg the answer is
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Answer:

1, 2, 4, 5 are correct

Explanation:

1) This is true because In a neutral atom, the number of positive charges (protons) is equal to the number of negative charges (electrons).

2) This is true because the mass of the atom which is made up of the protons and neutrons, is located in the tiny nucleus.

3) This is not true because the positively charged particles in the nucleus are called protons.

4) This is true because electrons move around the nucleus in diffuse areas known as orbitals.

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5 0
3 years ago
Scientist use conversion factors to express the given value of a unit different type of unit true or false
kykrilka [37]
True.

<span>Scientist use conversion factors to express the given value of a unit different type of unit</span>

4 0
3 years ago
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In the photoelectric effect, a photon with an energy of 5.3 × 10–19 J strikes an electron in a metal. Of this energy, 3.6 × 10–1
valentina_108 [34]

Answer:

The velocity of the photo electron is 6.11\times 10^5\ m/s.

Explanation:

Given that,

Supplied energy, E_s=5.3\times 10^{-19}\ J

Minimum energy of the electron to escape from the metal, E_e=3.6\times 10^{-19}\ J

We need to find the velocity of the photo electron. The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So,

5.3\times 10^{-19}\ J=3.6\times 10^{-19}\ J+K\\\\K=5.3\times 10^{-19}-3.6\times 10^{-19}\\\\K=1.7\times 10^{-19}\ J

The formula of kinetic energy is given by :

K=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1.7\times 10^{-19}}{9.1\times 10^{-31}}} \\\\v=6.11\times 10^5\ m/s

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4 0
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