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V125BC [204]
4 years ago
7

In a series circuit with three light bulbs...

Physics
1 answer:
Tomtit [17]4 years ago
5 0

Answer:

are you still looking for an answer?

Explanation:

because if you are i could give it to you. K?

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7. Why are cooking pans made of aluminum? {Explain using the specific heat value of
Dimas [21]
Cooking utensils, such as pots, pans and menu trays, are often made from aluminium because it is lightweight and conducts heat well, making it energy-efficient for heating and cooling. These properties also make it a preferred material for packaging.
6 0
2 years ago
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Crazy boy [7]

Answer:

The value is  u  =  3.23 *10^{7} \  m/s

Explanation:

From the question we are told that

   The diameter of the nucleus is d =  5.50 \ fm = 5.50 *10^{-15} \  c

   The charge of the proton that makes up the nucleus is  Q_2 = \frac{12}{2}  * 1.60 *10^{-19} =9.6*10^{-19} \ C

    The energy to be impacted is  KE_f  =  2.30 \  MeV  =  2.30 *10^{6} \  eV =   2.30 *10^{6}  *  1.60 *10^{-19} = 3.68*10^{-13} \  J

Generally the radius of the nucleus is mathematically represented as

         r  =  \frac{d}{2}

=>      r  =  \frac{5.50 *10^{-15}}{2}

=>      r  =  2.75 *10^{-15} \  m

Generally from the law energy conservation we have that

     Initial \  total  \  energy \ of the \  proton =  final \  total  \  energy \ of the \  proton

i.e

    T_i  =  T_f

Here

   T_i  =  KE_i + PE_i

Here KE_i is the initial kinetic energy which is mathematically represented as

       KE_I  =  \frac{1}{2}  *  m * u ^2

Here  PE_i is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  T_f is mathematically represented as

         T_f  =  KE_f + PE_f

Here  

        PE_f  is the final potential energy which is mathematically represented as

         PE_f  = \frac{k * Q_1 * Q_2}{r}

Here Q_1 is the charge on the proton with a value of Q_1 =  1.60 *10^{-19} \  C

So

        PE_f  = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}

=>     PE_f  = 5.027 *10^{-13 } \  J

So  

         KE_i + PE_i  =  KE_f + PE_f

=>       \frac{1}{2}  *  m * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

Here m is the mass of the moving proton with value m =  1.67*10^{-27} \  kg

So

       \frac{1}{2}  *  1.67*10^{-27}  * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

=>      u  =  \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5  *  1.67*10^{-27}} }

=>       u  =  3.23 *10^{7} \  m/s

5 0
3 years ago
You generally need a transformer to operate a doorbell because doorbells are designed to work with much smaller voltages than wh
mars1129 [50]

Answer: 300 turns

Explanation: In order to explain this problem we have to consider the relationship between the voltage for the primiry and secondary and the turns for their coils.

This expression is consequence of the Faraday law because the magnetic flux is the same for both coils then the induced emf are the same for both circuits.

They are reñated as follow:

Vs=Vp*Ns/Np  where Vs and Vp are the voltage for the secondary and primary coil, respectively.

Ns and Np are the turns for the secondary and primary coil, respectively.

Then we have:

Ns=Vs*Np/Vp= 16*2250/120=300

7 0
3 years ago
Need help answering this question for #30
dezoksy [38]
I think u would add them all up and then write down your answers
6 0
3 years ago
Read 2 more answers
When a star is moving away from us, the observed frequencies of light are lower than the actual frequencies. this illustration o
makvit [3.9K]
That's called the "red shift" of the star's spectrum, because red is the lowest frequency/longest wavelength in visible light.
8 0
4 years ago
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