119.7kPa
Explanation:
Given parameters:
Pressure of gas in balloon = 111kPa
Temperature of gas = 22°C
Final temperature = 45°C
Unknown:
Final pressure = ?
Solution:
Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.
At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.
P1 is the initial pressure
P2 is the final pressure
T1 is the initial temperature
T2 is the final temperature
convert from celcius to kelvin:
tK = 273 + tC
T1 = 273 + 22 = 295K
T2 = 273 + 45 = 318K
P2 = 119.7kPa
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The answer is B.It decreases the change of the momentum of the person
Explanation:
tilting it will raise the height of its center of gravity.
Answer:
a)α= 53.13°
b)The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
c)h=15 m
V=18.02 m/s
Explanation:
Speed of water ,u= 25 m/s
So the horizontal component of speed u = u cos α
Given that horizontal distance cover by water in 3 s is 45 m.
So We know that in projectile motion horizontal acceleration is zero.
In horizontal direction
Distance = Velocity x time
45 = u cos α x 3
u cos α = 45
45 = 25 cos α x 3
cos α = 45/75
α= 53.13°
So the velocity at the highest point = u cos α
The velocity at the highest point = 15 m/s
The acceleration at the highest point = 9.8
Now the velocity along vertical direction(Vo) = u sin α
Vo= 25 sin 53.13°
Vo =20 m/s
h=15 m
So at 15 m above the ground water will strike .
The y-component of velocity after 3 sec
Vy= Vo - g t
Vy = 20 - 10 x 3
Vy= -10 m/s
The horizontal component of velocity will remain 15 m/s.
The resultant velocity
V=18.02 m/s
Answer:
6.69 m/s
4.483 m
1.42s
Explanation:
Given that:
Initial Velocity, u = 0
Final velocity, v =?
Acceleration, a = 35m/s²
1.) using the relation :
v² = u² + 2as
v² = 0 + 2(35) * 64*10^-2m
v² = 70 * 0.64
v = sqrt(44.8)
v = 6.693
v = 6.69 m/s
B.) height from the ground, h0 = 2.2
How high ball went , h:
Using :
v² = u² + 2as
Upward motion, g = - ve
0 = 6.69² + 2(-9.8)*(h - 2.2)
0= 6.69² - 19.6(h - 2.2)
44.7561 + 43.12 - 19.6h = 0
19.6h = 44.7561 - 43.12
h = 87.8761 / 19.6
h = 4.483 m
C.)
vt - 0.5gt² = h - h0
6.69t - 0.5(9.8)t²
6.69t - 4.9t² = 1.83 - 2.2
-4.9t² + 6.69t + 0.37 = 0
Using the quadratic equation solver :
Taking the positive root:
1.4185 = 1.42s
