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ioda
3 years ago
9

Part A

Physics
1 answer:
Gemiola [76]3 years ago
8 0

The Mass of the barter and the ball is 3.1kg

Data Given;

  • F = 1.1*10^-9N
  • r = 0.76m
  • G = 6.67*10^-11 m^3 kg^-1 s^-1

Assuming the barter and the ball have equal mass, we can apply gravitational force formula.

<h3>Gravitational Force</h3>

F = \frac{Gm_1m_2}{r^2}

This is product of the mass of the two bodies and divided by the square of their distance apart.

Substituting the values into the formula

F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2}  \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg

From the calculations above, the mass of the barter and the ball is 3.1kg

Learn more on gravitational force here;

brainly.com/question/11359658

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e = 1.21 mV

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