Question

Part A

Answer 1

The Mass of the barter and the ball is 3.1kg

Data Given;

• F = 1.1*10^-9N
• r = 0.76m
• G = 6.67*10^-11 m^3 kg^-1 s^-1

Assuming the barter and the ball have equal mass, we can apply gravitational force formula.

Gravitational Force

$F = \frac{Gm_1m_2}{r^2}$

This is product of the mass of the two bodies and divided by the square of their distance apart.

Substituting the values into the formula

$F = \frac{Gm_1m_2}{r^2\\}\\m_1 = m_2 = m\\1.1*10^-^9=\frac{6.67*10^-^1^1*m^2}{0.76^2} \\m^2 = \frac{1.1*10^-^9*0.76^2}{6.67*10^-^1^1} \\m^2 = 9.525\\m = \sqrt{9.525}\\m =3.086=3.1kg$

From the calculations above, the mass of the barter and the ball is 3.1kg

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