Answer:
Measure 74.2 g Na2CO3 and add H20 until the final homogeneous solution has a volume of 7.00 L
Explanation:
The best procedure is
Mole of
= 0.700 mol
The mass of
= 74.2 g
So as per the above calculation, the option 3 is correct as the solution volume is 7.00 L so the same is to be considered
hence, all other options are wrong
You would observe, trying to identify if there's a minimum difference in each beaker. Like, colour, or using an <em>bagueta </em>(idk how to say it in english), churning it or something like that.
For my opinion 2nd last statement is better
Answer:
2.8 × 10² g
Explanation:
Given data
Step 1: Convert 25°C to the absolute scale
When working with gases, we have to convert the temperatures to the Kelvin scale, using the following expression.
K = °C + 273.15 = 25°C + 273.15 = 298 K
Step 2: Calculate the moles of chlorine gas
We will use the ideal gas equation.
Step 3: Calculate the mass of chlorine gas
The molar mass of Cl₂ is 70.91 g/mol. Then,