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cupoosta [38]
2 years ago
6

Solve y^2 = -64, where y is a real number

Mathematics
2 answers:
Firlakuza [10]2 years ago
5 0

Answer:

There is no solution to this equation in the Real number system

Step-by-step explanation:

There is no number which squared could render a negative number.

so

y^2=-64

has NO SOLUTIONS in the Real number system. the equation has solutions only if we expand the solution set to the complex numbers.

zavuch27 [327]2 years ago
3 0

Answer:

N/A, y is NOT a real number.

Explanation:

<em> To solve for y, you would have to take the square root of both sides of the equation</em>

<em>if one of the sides is a negative number (which is the case currently), there is no solution.</em>

<em>If -64 was positive, then y could be solved for, but as it is negative, that is not possible.</em>

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