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alisha [4.7K]
3 years ago
13

What’s the value of x? :/

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

x = 27

Step-by-step explanation:

According to congruent chords and arcs theorem, if \overline{XY} \cong \overline{ZY} then \arc{XY} \cong \arc{ZY}.

This means that \arc{XY} = \arc{ZY} = (6x - 20) degrees

Thus:

\arc{XY} + \arc{ZY} + \arc{ZX} = 360 (full circle = 360°)

\arc{XY} = (6x - 20)

\arc{ZY} = (6x - 20)

\arc{ZX} = 76

Plug in the values into the equation

(6x - 20) + (6x - 20) + 76 = 360

6x - 20 + 6x - 20 + 76 = 360

Add like terms

12x + 36 = 360

Subtract 36 on both sides

12x = 360 - 36

12x = 324

Divide both sides by 12

x = 27

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An equilateral triangle has a side length of 6. What is the height of the triangle?
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<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>

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<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>

<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>

<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
</span>
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