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scoray [572]
3 years ago
15

The graph of a line passes through the points (0,-2) and (6,0). What is the equation of the line?

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

y=1/3x-2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-2))/(6-0)

m=(0+2)/6

m=2/6

simplify

m=1/3

y-y1=m(x-x1)

y-(-2)=1/3(x-0)

y+2=1/3(x)

y+2=1/3x

y=1/3x-2

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D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

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D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

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