Calculate the deceleration (in m/s2) of a snow boarder going up a 2.65° slope assuming the coefficient of friction for waxed woo
d on wet snow. the equation a = g(sin(θ) − μk cos(θ)) for a snow boarder going downhill may be useful, but be careful to consider the fact that the snow boarder is going uphill. (enter the magnitude.) m/s2
The answer: to solve this problem, we can use newton's second law
F=MxA M is the mass of the object in motion A is its acceleration (or deceleration) F the sum of all exterior forces in our case the exterior forces are Fk (the friction force) and P (force of gravity)
In fact, Fk is positive because the motion is upward, its value is Fk=μk MgcosΘ and P=MgsinΘ
so we have F=MxA= μk MgcosΘ + MgsinΘ, and from where A =μk gcosΘ + gsinΘ μk=0.1 (coefficient of static friction on ice)
