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Georgia [21]
3 years ago
6

Calculate the deceleration (in m/s2) of a snow boarder going up a 2.65° slope assuming the coefficient of friction for waxed woo

d on wet snow. the equation a = g(sin(θ) − μk cos(θ)) for a snow boarder going downhill may be useful, but be careful to consider the fact that the snow boarder is going uphill. (enter the magnitude.) m/s2
Physics
1 answer:
MAVERICK [17]3 years ago
8 0
The answer:
to solve this problem, we can use newton's second law

F=MxA
M is the mass of the object in motion
A is its acceleration (or deceleration)
F the sum of all exterior forces 
in our case
the exterior forces are Fk (the friction force) and P (force of gravity)

In fact, Fk is positive because the motion is upward, its value is
Fk=μk MgcosΘ
and P=MgsinΘ

so we have F=MxA= μk MgcosΘ + MgsinΘ, and from where 
A =μk gcosΘ + gsinΘ
μk=0.1 (coefficient of static friction on ice)

A=0.1x9.8xcos2.65° + 9.8xsin2.65° =0.97 + 0.45 = 1.42 m/s²

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But the Sun isn't actually yellow; it's just an illusion caused by the Earth's atmosphere. The powerful processes happening inside the Sun are so robust that it emits every color of light imaginable. Together, these colors form a pure white light, which is precisely what you'd see from space.

Hoped I helped

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3 years ago
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How is the direction of current defined by convention
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Answer: The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.

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3 years ago
While Robert was helping his father in the garden, he pushed a shovel into the ground to dig a hole in the dirt. He picked up a
makvit [3.9K]

Work done is given by the change in kinetic energy of an object

  • The kinetic energy of the shovel, the shrub, and in Robert's movement were changed, therefore, work is done in the given processes,

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

  • In option <em>A</em>, pushing the shovel into ground (to dig out the dirt) the requires the application of a force (push) over a distance, (into and out of the ground) therefore work is done
  • In option <em>B</em>, picking the shrub up gives it gravitational potential energy, therefore, work is done
  • In option <em>C</em>, carrying the shrub to the hole does visible work
  • In option <em>D</em>, holding the shrub while lowering it into the hole does work by preventing the shrub from falling randomly

Therefore, <u>work is done in the given processes</u>

Learn more about work-energy theorem here:

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7 0
3 years ago
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a c
Aneli [31]

Answer

given,

x = (3.9 cm)sin[(9.3 rad/s)πt]

general equation of displacement

x = A sin ω t

A is amplitude

now on comparing

c) Amplitude  =3.9 cm

a) frequency =

     f = \dfrac{\omega}{2\pi}

     f = \dfrac{9.3\pi}{2\pi}

           f = 4.65 Hz

b) period of motion

        T= \dfrac{1}{f}

        T= \dfrac{1}{4.65}

        T = 0.215 s

d) time when displacement is equal to x= 2.6 cm

x = (3.9 cm)sin[(9.3 rad/s)πt]

2.6 = (3.9 cm)sin[(9.3 rad/s)πt]

sin[(9.3 rad/s)πt] = 0.667

9.3 π t = 0.73

t = 0.025 s

4 0
3 years ago
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