Complete Question
A voltaic cell utilizes the following reaction and operates at 298 K:
3Ce4+(aq)+Cr(s)→3Ce3+(aq)+Cr3+(aq).
What is the emf of this cell under standard conditions? Express your answer using three significant figures.
Answer:
The value is 
Explanation:
From the question we are told that
The ionic equation is

Now under standard conditions the reduction half reaction is

And the oxidation half reaction is

The emf of this cell under standard conditions is mathematically represented as

substituting values


Answer:
88.89kg
Explanation:
The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.
Answer:
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