Kinetic energy= 1/2mv^2
=1/2*130*6^2
=2340J
Answer:
2. Smaller value of q = 1/4Q
3. Larger value of q = 3/4Q
Explanation:
1. Please check the attachment for the solution of part 1. Due to time factor I couldn't type out the solution properly.
2. The smaller value is
F = 75% = 75/100
= 3/4 * Q²/16piEod² ---3
When we equate 1 and 3
We get 3Q²/16 = Qq - q² from here we cross multiply to get
3Q² = 16(Qq-q²)
3Q² = 16Qq-16q²
16q² - 16Qq + 3Q² = 0
When solve this out using the quadratic equation formula, we have:
Q/2 +- 2Q/8
We can get the smaller value of q as
Q/2-2Q/8
Solve using LCM we get
2Q/8 = 1/4Q = Q/4
C. The larger value of q
Q/2+2Q/8
= 6Q/8
= 3Q/4
Please use the attachment it will guide you to understand this better.
Explanation:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.
This is what I got:
Net force in the Y direction:
ΣFy = T1 - T2
F = ma
ma = T1 - T2
Isolate for T2
ma - T1 = -T2
Multiply by -1
T1 - ma = T2
100 - (3)(2) = T2
100 - 6 = T2
T2 = 94 N
The main requirement for a good conductor of electricity is to have a lot of valence electrons. Valence electrons are the electrons of the outer shells of atoms not bound with other atoms (for example through covalent bounds). These electrons are "free to escape" as soon as an electric field with enough intensity is applied to the material, and therefore these electrons will be free to move in the material producing an electric current.