A bond between a positively-charged particle and a negatively-charged particle is a(n) ______

A heavy boy and a lightweight girl are balanced on a massless seesaw. If they both

Len [333]

Answer:

D. Nothing will happen; the seesaw will still be balanced.

Explanation:

D. Nothing will happen; the seesaw will still be balanced. Since both toruqes or momentums respect to the center have changed in the same amount (one-half their original distance) the seesaw will remain balanced, if the children change distance in a different amount then it will be out of balance

3 0

3 years ago

Read 2 more answers

You observe two stars over the course of a year (or more) and find that both stars have measurable parallax. (1 arc second is 1/

Ierofanga [76]

Answer:

Star X is much closer since it is at a distance 1 parsec from the Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months.

The distance between the Earth and the Sun is 150000000 Km. That distance is also known as an astronomical unit (1AU).

The parallax angle can be defined in the following way:

$\tan{p} = \frac{1AU}{d}$

Where d is the distance to the star.

$p('') = \frac{1}{d}$ (1)

Equation (1) can be rewritten in terms of d:

$d(pc) = \frac{1}{p('')}$ (2)

Equation (2) represents the distance in a unit known as parsec (pc).

Case of Star X (p('') = 1):

Using equation 2 the distance of star X can be known:

$d(pc) = \frac{1}{1}$

$d(pc) = 1 pc$

So, star X is at 1 parsec from Earth.

Case of Star Y ( $p('') = \frac{1}{2}$ ):

$d(pc) = \frac{1}{(\frac{1}{2})}$

$d(pc) = 2 pc$

So, star Y is at 2 parsecs from the Earth.

Hence, star X is much closer.

Reminder:

Notice that in equation 2 the distance is inversely proportional to the parallax angle, so if the parallax angle decreases, the distance increases.

5 0

3 years ago

The anode heel affect 1. should be considered when the structure of interest is more than 43 inches long. 2. is a variation in p

DaniilM [7]

Answer:

Option 2. and 3.

Explanation:

Anode heel effect or simply heel effect is observed in X-ray tubes.

It is the change in the intensity of the emitted X-rays from the anode and this intensity is direction dependent and depends on the direction of the emitted X-rays along the axis of anode-cathode.

This effect results from the absorption of X-rays prior to leaving the anode, their production source.

The absorption of photons is more in the anode heel than the toe of the anode which results in the anode heel effect.

7 0

3 years ago

An astronaut in her space suit has a total mass of 87.0kg including suit and oxygen tank. Her tether line loses its attachment t

Shtirlitz [24]

Answer:

Explanation:

a )

In space due to weightlessness both astronaut and her oxygen tank will float .

when she throws the tank away from spacecraft , she will have a velocity in opposite direction ie towards the spacecraft . This happens due to conservation of momentum . She creates a momentum away so that she can get a momentum towards the spaceship.

So

m₁ v₁ = m₂v₂

12 x 8 = ( 87 - 12 ) x v₂

v₂ = 1.28 m /s

Time allowed = 2 x 60

= 120 s

So maximum distance upto which she can remain away from spacecraft

= 120 x 1.28

= 153 m .

b )

The Newton's law which explains the theory behind it is "third law of motion" . This law gives law of conservation of momentum .

6 0

4 years ago

8.92 A 45.0 kg woman stands up in a 60.0 kg canoe 5.00 m long. She walks from a point 1.00 m from one end to a point I .00 m fro

omeli [17]

The distance that the canoe moves in this process is 1.29 meters.

We first have to find the center of mass

$X = \frac{MsXs+McXc}{Mw+Mc} \\\\$

Where

Ms = Woman's mass = 45

Mc = Canoe's mass = 60kg

Xs = position from left= 1 cm

Xc = position from left end of canoe's mass = 2.5cm

When we put these values into the equation we have:

$X=\frac{45*1+60*2.5}{45+60} \\\\= 1.857\\$

The center of gravity lies at the center of this boat. Therefore,

$Xc = \frac{L}{2} \\\\L = 5 m long\\\\\frac{5}{2} =2.5$

5.00 - 1. 00 = 4 meters

$\frac{45*4+60*2.5}{45+60} = 3.14meters\\\\$

To get the distance that is moved by this canoe

distance = 3.143-1.857

= 1.286

≈ 1.29 meters

The distance that the canoe moves in this process is 1.29 meters.

6 0

2 years ago

A bond between a positively-charged particle and a negatively-charged particle is a(n) _______ bond.