part 1
mass = ρ x V
mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg
PE (potential energy)= mgh
PE = 6608.2 kg x 9.81 x 403
PE = 2.61 x 10⁷ J
part 2
megaton of TNT (Mt) =4.2 x 10¹⁵ J
convert PE to Mt:
2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt
Where are the questions so that I can deliver a more accurate answer.
Answer:
This is True
Explanation:
I just did this exact unit in bio last week I hope this helps ;)
Answer:
Explanation:required formula is
W 1=F*S
W1=work done by Sam =?
F=force applied by sam=150N
S=displacement =10m
again
W2=F*S
W2=work done by friction =?
S=displacement =10m
F=friction =25N
W=W1-W2=net work done
please feel free to ask if you have any questions
To solve this problem, we are going to use the formula for
work which is Fd where x and y are measured separately.
X direction: W = 13.5 x 230 = 3105 Joules
Y direction: W = -14.3 x -165 = 2360 Joules
So the total work is getting the sum of the two: 3105 + 2360
= 5465 Joules
