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Andrei [34K]
3 years ago
7

A gas has an initial volume of 21.7 L at a pressure of 0.4 atm and a temperature of 252 K. The pressure of the gas increases to

2 atm as the temperature increases to 323 K. What is the final volume of the gas?
Physics
2 answers:
elena-s [515]3 years ago
7 0
Theeeeeeeeeeeeeeeee answer is 5.6 L
Sloan [31]3 years ago
3 0
According to the combined gas law: (P₁*V₁)/T₁=(P₂*V₂)/T₂, where P is the pressure, V is the volume and T is the temperature.

P₁=0.4 atm = 40530 Pa
V₁=21.7 L = 0.0217 m³
T₁=252 K
P₂=2 atm = 202650 Pa
T₂=323 K
V₂=?

We need to solve for V₂:

(P₁*V₁)/T₁=(P₂*V₂)/T₂

(T₂*P₁*V₁)/T₁=P₂*V₂

(T₂*P₁*V₁)/(T₁*P₂)=V₂, now we plug in the numbers and get:

V₂=0.00556 m³, and we can see that with increased temperature and pressure the volume V₂ has decreased. 

When we transfer V₂=0.00556 m³ to liters we get that 0.00556 m³=5.56 L. That can be rounded up to V₂=5.6 L.
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vovikov84 [41]

Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

y=y_{o}+Vo sin \theta t + \frac{g}{2}t^{2} (2)

Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

\theta=0\° since we are told the pencil rolls <u>horizontally</u> before falling

t is the time since the pencil falls until it hits the ground

y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity, always acting vertically downwards

Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

Finally:

V_{o}=0.55 m/s

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Musya8 [376]

Answer:

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Explanation

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A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving
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Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

m_av_a + m_sv_s = 0

Where m_a = 92kg is the mass of the astronaut, m_s = 1200kg is the mass of the satellite, v_s = 0.14 m/s is the speed of the satellite. We can calculate the speed v_a of the astronaut:

v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

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F = 176,000 N

8 0
3 years ago
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