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kvasek [131]
3 years ago
11

The mass of a star can be determined by studying ___.

Physics
2 answers:
oksian1 [2.3K]3 years ago
7 0

Answer:

C. Binary star systems

Explanation:

Citrus2011 [14]3 years ago
4 0
Answer: C. Binary star systems

Let’s see your options:

a) The <em>color of the star</em>: the color is not used in calculating the mass of a star, because it has no relation to it. Think about a red supergiant and a red dwarf: they have the same color, but they are completely different stars, with respectively a big and a small mass.

b) <em>Kepler’s laws</em>: these laws can be applied in what is called the “approximation of 1 body”, which means that is assumed that one body has a much bigger mass than the other and can be considered at rest. This is the case of a star-planet system and the mass that can be calculated is that of the planet.

c)<em> Binary star systems</em>: these are the only cases in which is possible the direct measure of the mass of the stars. Binary systems are classified as follows:
- Visual binaries: each star can be resolved and the motion around the center of mass can be measured.
- Astrometric binaries: only one star is visible, but the presence of the companion can be inferred by the movement of the first star around the system’s center of mass.
- Eclipse binaries: the two stars are not resolved (separated), but the luminosity varies periodically when one star eclipses the other.
- Spectroscopic binaries: the two stars are not resolved, but their spectrum reveals that they are a binary system.
In all these cases we have a “two-body problem” that can be solved by changing system of reference: the motion of bodies 1 and 2 is equivalent to the motion of a body of mass equal to the system’s reduced mass \mu =  \frac{M_{1} \cdot M_{2}}{M_{1} + M_{2}} moving in the potential generated by the total mass (M1 + M2) considered at rest. Hence, we can determine the masses of the two stars. 
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2 years ago
An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-f
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3 years ago
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 tesla?
Nonamiya [84]

Complete Question:

When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.

Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?

Answer:

ΔE = 1.224 * 10⁻²² J

Explanation:

In the 6f state, the orbital quantum number, L = 3

The magnetic quantum number, m_{L} = -3, -2, -1, 0, 1, 2, 3

The change in energy due to Zeeman effect is given by:

\triangle E = m_{L} \mu_{B} B

Magnetic field B = 2.02 T

Bohr magnetron, \mu_{B} = 9.274 * 10^{-24} J/T

\triangle E = 6 * 9.274 * 10^{-24} * 2.2\\

ΔE = 1.224 * 10⁻²² J

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A cube slides down the surface of a ramp at a constant velocity. What is the magnitude of the
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3 years ago
Read 2 more answers
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