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zepelin [54]
3 years ago
7

Simplify (3a) (a^-3) =

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

3 a^(-2)

3 / a^2

Step-by-step explanation:

(3a) (a^-3)

Multiply

3 a^1 * a^-3

Since we are multiplying, we add the exponents

3 a^ ( 1-3)

3 a^(-2)

If  you are not supposed to leave a negative exponent

x^-b = 1 / x^b

3 / a^2

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A six-faced die is rolled .
STatiana [176]

Answer:

[A] 2/6

[B] 1/2

Step-by-step explanation:

Given:

A six-faced die is rolled .

To Find:

Find the probability of it landing on a value more than 4

Find the probability of it landing on an even number

Part A:

Knowing that a six-faced die has six number on it (1,2,3,4,5,6)

Thus, the probability of it landing on an value more than 4 is 2/6.

Because 5 and 6 is more than 4

Part B:

1,3,5 = Odd

2,4,6 = Even

Thus, the probability of it landing on an even number is 3/6 Simplify 1/2 . Which also is 50%.

<em>~Lenvy~</em>

8 0
2 years ago
A=9y+3yx<br> Solve for y
algol13
A = y(9 + 3x) factor y out of 9y+3yx, then devided both sides by (9+3x)
A/(9+3x) = y

7 0
4 years ago
Read 2 more answers
Can someone please answer my question before this one go to my profile to view
Elenna [48]

Answer: Okay, what's the question?

Step-by-step explanation:

7 0
3 years ago
Victoria had $200 in her account at the end of one year. At the first of each subsequent year she deposits $15 into the account
telo118 [61]

Answer:

A(t) = 200+15t(1+0.02)^{t}

Step-by-step explanation:

Since the interest is calculated on the new balance every year.

Hence the formula used for compound interest is:

A = P(1+\frac{r}{n}^{nt}

where, A =Amount after t years

P =Principal amount

200 is the initial balance and Since, here the $15 is added to the balance each year. Therefore, P = 200+15t

r = rate each year (0.02)

t = time (in years) (t)

n = no. of times the interest is compounded in a year (n=1)

Therefore, the recursive formula is:

A(t) = 200+15t(1+0.02)^{t}

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAAAAPPPPPPP
ddd [48]
Distribute ^4 to both 2 and q^5

2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20

16(q^20) = 16q^20 

16q^20 is your answer

hope this helps
3 0
3 years ago
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