Pls I need it for a testI’ll give out 20 points

3. Find the mean and the median of this data set: 9,6,5, 3, 28, 6, 4, 7.<br>

BARSIC [14]

Answer:

Mean= 8.5

Median= 6

Step-by-step explanation:

3,4,5,6,6,7,9,28

Median= Middle (If two middle number, add and divide by 2)

Mean= (3+4+5+6+6+7+9+28) ÷8

7 0

3 years ago

What is the solution to the equation fraction 1 over 4x = 5?

Amanda [17]

C) x=20
$x = 20$

6 0

3 years ago

Find the roots of the following function:<br><br> y = x2 − 7x − 30

DIA [1.3K]

Answer:

x = 3, −10

Step-by-step explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

6 0

3 years ago

Gertrude takes out a $5,500 subsidized stafford loan, which must be paid back in ten years. gertrude will graduate four years af

Leno4ka [110]

The total amount of interest will Gertrude pay by the time the subsidized Stafford loan is repaid is $2094.80.

<h3>What is compound interest?</h3>

Compound interest is the amount charged on the principal amount and the accumulated interest with a fixed rate of interest for a time period.

The formula for the final amount with the compound interest formula can be given as,

$A=P\times\left(1+\dfrac{r}{n\times100}\right)^{nt}\\$

Here, A is the final amount (principal plus interest amount) on the principal amount P of with the rate<em> r </em>of in the time period of <em>t.</em>

Gertrude will graduate four years after taking out the loan. if the loan has an interest rate of 6.8%, compounded monthly, and Gertrude makes monthly payments.

Put the values in the above formula as,

$5500=P_{mt}\times\left(1-\dfrac{6.8}{12\times100}\right)^{-12\times10}\\P_{mt}=63.29$

In the 10 years, the refund she gets,

$A_r=63.29\times12\times100\\A_r=7594.8$

Interest paid by her is,

$I=7594.8-5500\\I=2094.8$

Thus, the total amount of interest will Gertrude pay by the time the subsidized Stafford loan is repaid is $2094.80.

Learn more about the compound interest here;

brainly.com/question/24274034

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

2 years ago