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zaharov [31]
3 years ago
13

What is the equation of a circle with center (6,-4) and radius 6?

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

(x-6)^{2} + (y+4)^{2}=36

Step-by-step explanation:

(x-h)^{2} + (y-k)^{2}=r^{2}

h=6

k=-4

r=6

(x-6)^{2} + (y+4)^{2}=6^{2}

x^{2} -12x+36 + y^{2} +8y+16=36\\\\x^{2} +y^{2} -12x +8y +52-36 = 0\\\\x^{2} +y^{2} -12x +8y+ 16 = 0

torisob [31]3 years ago
8 0

Answer:

(x - 6)² + (y + 4)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (6, - 4) and r = 6, hence

(x - 6)² + (y - (- 4))² = 6², that is

(x - 6)² + (y + 4)² = 36 ← equation of circle

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elaine has a rectangular gift wrapper that measure 30 cm by 25 cm she wants to cut it into square sheets of the same size to be
12345 [234]

Answer:

Square length of 5cm

Step-by-step explanation:

Given

Length = 30cm

Width = 25cm

Required

Determine the possible measure of square from the rectangular sheet

To do this, we simply calculate the greatest common factor (GCF) of the dimension of the rectangle.

30 = 2 * 3 * 5

25 = 5 * 5

The common factor is: 5

<em>Hence, the side length of the square is 5cm</em>

6 0
3 years ago
What is the probability that a randomly selected contestant won a prize, given that the contestant was female write the probabil
pantera1 [17]

We have given the table of number of male and female contestants who did and did not win prize

The probability that a randomly selected contestant won prize given that contestant was female is

P(contestant won prize / Contestant was female)

Here we will use conditional probability formula

P(A/B) = \frac{P( A and B)}{P(B)}

Let Event A = selected contestant won prize and

event B = selected contestant is famale

Then numerator entity will

P(A and B) = P(Contestant won prize and Contestant is female)

= Number of female contestant who won prize / Total number of contestant

= 3 /(4+9+3+10)

= 3 / 26

P(A and B) = 0.1153

P(B) = P(contestant is female )

= Number of female contestant / Total number of contestants

= (3+10) / 26

P(B) = 0.5

Now P(A / B) = \frac{P( A and B)}{P(B)}

= 0.1153 / 0.5

P(A / B) = 0.2306

The probability that randomly selected contestant won prize given that contestant is female is 0.2306

Converting probability into percentage 23.06%

The percentage that randomly selected contestant won prize given that contestant is female is 23%

3 0
3 years ago
It costs a publishing company $0.55 to print one copy of a certain novel. This company paid $725,000 for the rights to the novel
Dmitrij [34]

Answer:

The correct answer is b. 116,900

The publishing company must sell 116,900 copies of the book to break even.

Step-by-step explanation:

Each book costs 0.55 to make and the company can sell it at 6.75, which means that the company earns 6.20 from each book, this is called the net value. If you divide the amount htat the company paid for the rights by the net value you can find the total number of copies that the company has to sell to break even.  

# books = $725,000/$6.20 = 116935 or approximately 116900 copies of the book.

8 0
3 years ago
Which representation of a transformation on a coordinate grid does not preserve congruence?
Alex17521 [72]

Answer:

B

Step-by-step explanation:

Consider all options:

A. Transformation with the rule

(x,y)\rightarrow (x,-y)

is a reflection across the x-axis.

Reflection across the x-axis preserves the congruence.

B. Transformation with the rule

(x,y)\rightarrow \left(\dfrac{7}{8}x,\dfrac{7}{8}y\right)

is a dilation with a scale factor of \frac{7}{8} over the origin.

Dilation does not preserve the congruence as you get smaller figure.

C. Transformation with the rule

(x,y)\rightarrow (x+6,y-4)

is a translation 6 units to the right and 4 units down.

Translation 6 units to the right and 4 units down preserves the congruence.

D. Transformation with the rule

(x,y)\rightarrow (y,-x)

is a clockwise rotation by 90^{\circ} angle over the origin.

Clockwise rotation by 90^{\circ} angle over the origin preserves the congruence.

3 0
3 years ago
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anygoal [31]

Answer:

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8 0
3 years ago
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