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zaharov [31]
3 years ago
13

What is the equation of a circle with center (6,-4) and radius 6?

Mathematics
2 answers:
sergey [27]3 years ago
8 0

Answer:

(x-6)^{2} + (y+4)^{2}=36

Step-by-step explanation:

(x-h)^{2} + (y-k)^{2}=r^{2}

h=6

k=-4

r=6

(x-6)^{2} + (y+4)^{2}=6^{2}

x^{2} -12x+36 + y^{2} +8y+16=36\\\\x^{2} +y^{2} -12x +8y +52-36 = 0\\\\x^{2} +y^{2} -12x +8y+ 16 = 0

torisob [31]3 years ago
8 0

Answer:

(x - 6)² + (y + 4)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (6, - 4) and r = 6, hence

(x - 6)² + (y - (- 4))² = 6², that is

(x - 6)² + (y + 4)² = 36 ← equation of circle

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If a line is parallel to another, the slopes of both lines are the same. So for this problem, you can infer that the slope of the line you're trying to find is 3.

To find the actual equation of the line, you can use the given coordinates and plug them into the point slope form:

y - y1 = m(x - x1)

plug the given y coordinate into y1 and the given x coordinate into x1. m is the slope, so plug in 3 for m.

y - 1 = 3(x +2) Use distributive property for right side of equation

y - 1 = 3x + 6 add 1 to both sides to cancel -1 on left side of equation and isolate y

Equation of line: y = 3x + 7


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3x3-27x=0<br> Solve by factoring a
Eddi Din [679]

After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Step-by-step explanation:

We need to solve by factoring:

3x^3-27x=0

Solving:

3x^3-27x=0

Taking 3x common:

3x(x^2-9)=0

Now using formula a^2-b^2=(a-b)(a+b)

3x((x)^2-(3)^2)=0\\3x(x-3)(x+3)=0

3x=0\,\,and\,\,x+3=0\,\,and\,\,x-3=0\\x=0\,\,and\,\,x=-3\,\,and\,\,x=3\\

So, After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Keywords: Factorization

Learn more about Factorization at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256
  • brainly.com/question/1414350

#learnwithBrainly

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