21.28s
Explanation:
This is a rate problem.
Number of parts produced = 225
Time taken to produce= 8hours
Rate of production is the amount of parts produced in a duration of time.
Now convert 8 hours to minute;
60 minutes = 1hr
8 hours = 60 x 8 = 480minutes
Now:
Rate of production = = 0.47parts/minute
Now, to produce 10 parts;
It takes;
0.47 parts to be produced in 1 minute
10 parts would be produced in = 21.28s
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Answer:
the change in the system internal energy is 20 J
Explanation:
The computation of the change in the system internal energy is as follows:
Since the volume remains constant so the work done would be zero
Now the change in the internal energy is
= Heat given to system - work done
= 20 J - 0
= 20 J
hence, the change in the system internal energy is 20 J
The same is to be considered
The glowing splint in the reaction of hydrogen gas and oxygen gas to form water provides the activation energy for the reaction.
<h3>Reaction of hydrogen gas and oxygen</h3>
A chemical reaction involves the combination of two or more substances to yield a new substance which is different from the starting materials. It may also involve the break up a substance.
Since energy is required for a chemical reaction to take place, the glowing splint in the reaction of hydrogen gas and oxygen gas to form water provides the activation energy for the reaction.
Learn more about activation energy: brainly.com/question/11334504
Following is the balanced <span>radioactive decay series:
</span><span>
Particle/radiations generated during the reaction are labeled in bold at end of reaction.
Care must be taken that, atomic number and atomic mass number should be balanced in each of these reactions.
1) 92 238U </span>→ <span> 90 234Th + 2 4He(</span>α particle<span>)
A = </span>90 234Th because alpha particle is emitted along with it. So atomic number of daughter element has to be 92 - 2 = 90. This corresponds to Th. <span>
2) 90 234Th </span>→<span> 91 234Pa + -1 0e (electron)
B = -1 0e i.e electron because after radioactive disintegration atomic number of daughter element (Pa) is +1 as compared to parent element (Th)
3) 91 234Pa </span>→<span> 92 234U + –1 0e (electron)
</span>C = 92 234U because electron is emitted along with it. So atomic number of daughter element has to be 91 - (-1) = 92. This corresponds to U. <span>
4) 92 234U </span>→ 90 230Th + 2 4He (α particle<span>)
</span><span>In this case, 92 234U undergoes nuclear disintegration to generate 90 230Th and alpha particle
5) 90 230Th </span>→<span> 88 226Ra + 2 4He </span>(α particle)
D = 88 226Ra because alpha particle is emitted along with it. So atomic number of daughter element has to be 90 - 2 = 88. This corresponds to Ra.
<span>6) 88 266Ra </span>→ 86 222Rn + 2 4He (α particle)
E = alpha particle because during nuclear disintegration, 88 266Ra is converted into 86 222Rn. Hence, for mass balance we have 88 - 86 = 2. It corresponds to alpha particles.
<span>
7) 86 222Rn </span>→<span> 84 218Po + 2 4He </span>(α particle)
Again, F = alpha particle because during nuclear disintegration, 86 222Rn is converted into 84 218Rn. Hence, for mass balance we have 86 - 84 = 2. It corresponds to alpha particles.
<span>
8) 84 218Po </span>→<span> 82 214Pb + 2 4He </span>(α particle)
G = 82 214Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.
<span>
9) 82 214Pb </span>→<span> 83 214Bi + -1 0e (electron)
H = </span>-1 0e because after radioactive disintegration atomic number of daughter element (Bi) is +1 as compared to parent element (Pb)<span>
10) 83 214Bi </span>→<span> 84 214Po + –1 0e (electron)
I = </span>84 214Po because electron is emitted along with it. So atomic number of daughter element has to be 83 - (-1) = 84. This corresponds to Po.<span>
11) 84 214Po </span>→<span> 82 210Pb + 2 4He </span>(α particle)
J = 82 210Pb because alpha particle is emitted along with it. So atomic number of daughter element has to be 84 - 2 = 82. This corresponds to Pb.