1)2(m+3)=-6
2m+6=-6
2m=-6-6
2m=-12
M=-12/2=-6
2)2m+6=-6
2m=-6-6
2m=-12
M=-12/2=-6
3)2m+6-6=-6-6
2m=-12
M=-12/2=-6
4)2m=-12
M=-12/2=-6
Given choices:
(1) division property of equality
(2) factoring the binomial
(3)completing the square
(4)subtraction property of equality
Answer : (2) factoring the binomial
Step 1: 
Step 2:![-c = a[x^2+\frac{b}{a} x]](https://tex.z-dn.net/?f=%20%20-c%20%3D%20a%5Bx%5E2%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%5D%20%20%20)
In step 2, 'a' is taken out from 
. when we take out 'a' we divide each term by 'a'. so it becomes ![a[x^2+\frac{b}{a} x]](https://tex.z-dn.net/?f=%20%20%20a%5Bx%5E2%2B%5Cfrac%7Bb%7D%7Ba%7D%20x%5D%20%20%20)
'a' is factored out in step 2. we call it as factoring a binomial.
I think it is false sorry if i am wrong
I'll answer 3 of these questions.
For future notice, make sure to limit yourself to asking at most, 3 individual questions per question. :)
1) r/10+4=5
Subtract both sides by 4.
(r/10+4)-4=(5)-4
r/10=1
Multiply both sides by 10.
(r/10)*10=(1)*10
r=10
2) n/2+5=3
Subtract 5 from both sides.
(n/2+5)-5=(3)-5
n/2=-2
Multiply both sides by 2.
(n/2)*2=(-2)*2
n=-4
3) 3p-2=-29
Add 2 to both sides.
(3p-2)+2=(-29)+2
3p=-27
Divide both sides by 3.
(3p)/3=(-27)/3
p=-9
Hope this helps.
-Benjamin
