16. A particular organ in the human

What is the specific activity (in Ci/g) if 1.65 mg of an isotope emits 1.56X10⁶α a particles per second?

marta [7]

The specific activity (in Ci/g) if 1.65 mg of an isotope emits 1.56X10⁶α a particles per second.

<h3>What is isotope?</h3>

Isotopes are two or more types of atoms with the same atomic number (number of protons in their nuclei) and periodic table position (and so belong to the same chemical element), but distinct nucleon numbers due to differing numbers of neutrons in their nuclei. While all isotopes of a given element have nearly identical chemical properties, their atomic weights and physical properties differ.

The term isotope is derived from the Greek roots isos and topos, which means that different isotopes of the same element occupy the same position on the periodic table. Margaret Todd, a Scottish doctor and writer, coined the phrase in 1913 as a recommendation to British chemist Frederick Soddy.

To learn more about isotopes visit:

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4 0

2 years ago

Is vinegar in water a true solution, suspension or colloid

nata0808 [166]

Answer:

Solution

Explanation:

Solution

4 0

3 years ago

PLEEEASSEEEE HELPPPPP!!!!!Take some time to research a utility plant. If there is one in your area, you may even visit it.

raketka [301]

Answer:

There are four laws of thermodynamics that define fundamental physical quantities (temperature, energy, and entropy) and that characterize thermodynamic systems at thermal equilibrium.

Explanation:

6 0

3 years ago

What is the mass of water that results from combining 2.0 g of hydrogen with 16.0 g of oxygen?

Feliz [49]

C. 18.0g. all you really have to do is add both of them together and you get your answer.

4 0

3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

2 years ago