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3 years ago

13

Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides b. c

ocamide DEA c. folic acid d. iron e. chromium ion f. peroxide g. lauryl glucoside h. disodium phosphate

1 answer:

GREYUIT [131]3 years ago

5 0

Answer:

B. cocamide DEA

C. folic acid

D. iron

G. lauryl glucoside

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Which neutral atom has 151 neutrons and 96 electrons

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The wavelength of a given region of the electromagnetic spectrum ranges from 1 x 10-11 - 1 x 10-8 meters. Which waves are found

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The electromagnetic spectrum consists of the full range of known electromagnetic waves. And among them, X-rays has the wavelength of the region 1*10-11 to 1*10-8 meters.

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When magnesium chloride reacts with water, 5.85 L HCl(g) is produced.

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Answer: How many moles of HCl was produced?

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4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

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3 years ago

How many grams of lead sulfide from when 10.0 g of lead are heated with 3.0 g of sulfur

zaharov [31]

The reaction forms 11.5 g PbS.

We have the masses of two reactants, so this is a <em>limiting reactant</em> problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

<em>Step 1</em>. <em>Gather all the information</em> in one place with molar masses above the formulas and everything else below them.

M_r: 207.2 32.06 239.28

Pb + S → PbS

Mass/g: 10.0 3.0

<em>Step 2</em>. Calculate the <em>moles of each reactant </em>

Moles of Pb = 10.0 g Pb × (1 mol Pb /207.2 g Pb) = 0.048 26 mol Pb

Moles of S = 30 g S × (1 mol S/32.06 g S) = 0.9357 mol S

S<em>tep 3</em>. Identify the <em>limiting reactant</em>

Calculate the moles of PbS we can obtain from each reactant.

<em>From Pb</em>: Moles of PbS = 0.048 26 mol Pb × (1 mol PbS/1 mol Pb )

= 0.048 26 mol PbS

<em>From S</em>: Moles of S = 0.9357 mol S × (1 mol PbS/1 mol S) = 0.9357 mol PbS

<em>Pb is the limiting reactant</em> because it gives the smaller amount of PbS.

<em>Step 4</em>. Calculate the <em>mass of PbS</em>.

Mass = 0.048 26 mol PbS × (239.28 g PbS/1 mol PbS) = 11.5 g PbS

The reaction produces 11.5 g PbS.

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3 years ago