Answer:
33.7 kg
Explanation:
Let's consider calcium phosphate Ca₃(PO₄)₂.
The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol and the molar mass of P is 30.97 g/mol. In 1 mole of Ca₃(PO₄)₂ (310.18 g) there are 2 × 30.97 g = 61.94 g of P. The mass of Ca₃(PO₄)₂ that contains 3.57 kg (3.57 × 10³ g) of P is:
3.57 × 10³ g × (310.18 g Ca₃(PO₄)₂/61.94 g P) = 1.79 × 10⁴ g Ca₃(PO₄)₂
A particular ore contains 53.1% calcium phosphate. The mass of the ore that contains 1.79 × 10⁴ g of Ca₃(PO₄)₂ is:
1.79 × 10⁴ g Ca₃(PO₄)₂ × (100 g Ore/ 53.1 g Ca₃(PO₄)₂) = 3.37 × 10⁴ g Ore = 33.7 kg Ore
Answer:
14.4 covers/hr.
Explanation:
First, we need to identify how much covers are produced in 1 hour, which will be total produced divided by the total time:
covers/hr = 120/10
covers/hr = 12
If the production will be increased by 20%, it means that new production will be the initial one plus 20% (0.20) of it:
12 + 0.20*12 = 14.4 covers/hr.
Answer:
Therefore, the oxidation state of sulphur atoms in Na2S2O3 is −2 and +6.
Answer:
H2O2 → H2O + 1/2O2
Explanation:
0.0800 mol of H2O2 decomposed into 0.0800 mol of H2O and 0.0400 mol of O2
H2O2 → H2O + 1/2O2 - Descomposition reaction.
Because same charges repel each other while opposite charges attract. :)
