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Arturiano [62]
3 years ago
10

How many seconds does it take to deposit 0.94 g of Ni on a decorative drawer handle when 14.9 A is passed through a Ni(NO3)2 sol

ution? Molar mass of Ni is 58.69 g/mole. Faraday constant=96485 C/mole. Enter numbers into 1 decimal places.
Chemistry
1 answer:
Goshia [24]3 years ago
3 0

Answer:

Time take to deposit Ni is 259.02 sec.

Explanation:

Given:

Current I = 14.9 A

Faraday constant = 96485 \frac{C}{mole}

Molar mass of Ni = 58.69 \frac{g}{mole}

Mass of Ni = 0.94 g

First find the no. moles in Ni solution,

Moles of Ni = \frac{0.94}{58.69}

                   = 0.02 mol

From the below reaction,

  Ni^{2+}  + 2e ⇆ Ni_{(s)}

Above reaction shows "1 mol of Ni^{2+} requires 2 mol of electron to form 1 mol of Ni_{(s)} "

So for finding charge flow in this reaction we write,

    = 0.02 \times \frac{2  }{1 }  \times 96485 \frac{C}{mol}

Charge flow = 3859.4 C

For finding time of reaction,

  I = \frac{q}{t}

Where q = charge flow

   t = \frac{q}{I}

   t = \frac{3859.4}{14.9}

   t = 259.02 sec

Therefore, time take to deposit Ni is 259.02 sec.

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