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3 years ago

If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?

Chemistry

1 answer:

Tanya [424]3 years ago

4 0

Answer:

$\large \boxed{\text{257 g}}$

Explanation:

We can convert the formula units to moles and then use the molar mass to find the mass.

1. Moles of Pb(MnO₄)₂

$n = 3.48 \times 10^{23}\text{ formula units} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ formula units}} = \text{0.5779 mol}$

2. Mass of Pb(MnO₄)₂

$\text{Mass} = \text{0.5779 mol} \times \dfrac{\text{445.07 g}}{\text{1 mol u}} = \text{257 g}\\\\\text{The mass of lead(II) permanganate is $\large \boxed{\textbf{257 g}}$}$

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A student dissolved 3.50g of copper (II) nitrate in water and mixed it with a solution of sodium carbonate. The student recovere

Arisa [49]

Answer: If the theoretical yield is 2.35g then the percent yield is 80.4%

Explanation:

Given: Actual yield = 1.89 g

Theoretical yield = 2.35 g

Formula used to calculate the percentage yield is as follows.

$Percent yield = \frac{actual yield}{theoretical yield} \times 100$

Substitute the values into above formula as follows.

$Percent yield = \frac{actual yield}{theoretical yield} \times 100\\= \frac{1.89}{2.35} \times 100\\= 80.4 percent$

Thus, we can conclude that if the theoretical yield is 2.35g then the percent yield is 80.4%

3 0

3 years ago

Chandra wants to know how many moles are contained in 150.0 g ccl4 (carbon tetrachloride). what quantity of ccl4 should she use

Fynjy0 [20]

The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CCl₄</h3>

Mass of CCl₄ = 30 g
Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 150 / 154

Mole of CCl₄ = 0.974 mole

Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.

Learn more about mole:

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8 0

2 years ago

Which statement regarding this equation is TRUE?

noname [10]

Answer:

iron (III) oxide is a gas

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2 years ago

What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?

scoundrel [369]

Answer:

b. Beta emission, beta emission

Explanation:

A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

8 0

3 years ago

At 73.0 ∘c , what is the maximum value of the reaction quotient, q, needed to produce a non-negative e value for the reaction so

damaskus [11]

Here we will use the general formula of Nernst equation:

Ecell = E°Cell - [(RT/nF)] *㏑Q

when E cell is cell potential at non - standard state conditions

E°Cell is standard state cell potential = - 0.87 V

and R is a constant = 8.314 J/mol K

and T is the temperature in Kelvin = 73 + 273 = 346 K

and F is Faraday's constant = 96485 C/mole

and n is the number of moles of electron transferred in the reaction=2

and Q is the reaction quotient for the reaction
SO42-2(aq) + 4H+(aq) +2Br-(aq) ↔ Br2(aq) + SO2(g) +2H2O(l)

so by substitution :

0 = -0.87 - [(8.314*346K)/(2* 96485)*㏑Q → solve for Q

∴ Q = 4.5 x 10^-26

6 0

3 years ago