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Black_prince [1.1K]
3 years ago
5

Are the phases of the moon the same everywhere on earth

Physics
1 answer:
timama [110]3 years ago
4 0
Yes. Everybody on Earth sees the same moon phase at the same time.
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A solid non-conducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a radius r (r <
Svet_ta [14]

Answer:  

Hence the answer is E inside = KQr_{1} /R^{3}.

Explanation:  

E inside = KQr_{1} /R^{3}  

so if r1 will be the same then  

E  \begin{bmatrix}Blank Equation\end{bmatrix} proportional to 1/R3  

so if R become 2R  

E becomes 1/8 of the initial electric field.

8 0
2 years ago
Read 2 more answers
According to the photon energy formula, tripling the frequency of the radiation from a monochromatic source will change the ener
Harrizon [31]

Answer:

By a factor of 3

Explanation:

In the photon energy formula , frequency and the energy content have a direct relationship. This means anything that is done to one of the parameters is the same that will be done to the other to have a balance.

In this equation: Energy=plank’s constant * frequency.

Energy is directly proportional to frequency.

3 0
3 years ago
Read 2 more answers
Kelli weighs 440 N, and she is sitting on a playground swing that hangs 0.41 m above the ground. Her mom pulls the swing back an
kifflom [539]

Answer:

Explanation:

Initial height from the ground = .41 m

Final height = 1m

Height by which Kelli was raised ( h )= .59 m

When she passes through the lowest point , she loses P E

= mgh

= 440 x .59

= 259.6 J

kinetic energy possessed by her

= 1/2 mv²

= .5 x (440/9.8) x 2²

= 89.8 J

Difference of energy is lost due to work by  air friction

work done by  friction = 89.8 - 259.6

= - 169.8 J

4 0
3 years ago
Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

- For M1, the only two forces acting on it are the force of gravity M_1 g (downward) and the tension in the string T (upward). So we can write

M_1 g - T = M_1 a

where

M_1 is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
According to newton, doubling the distance between two interacting objects:
Furkat [3]

Answer:

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).

Explanation:

hope his helps

8 0
2 years ago
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