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Black_prince [1.1K]

3 years ago

5

Are the phases of the moon the same everywhere on earth

1 answer:

timama [110]3 years ago

4 0

Yes. Everybody on Earth sees the same moon phase at the same time.

You might be interested in

If fuel consumption is 80 pounds per hour and groundspeed is 180 knots, how much fuel is required for an airplane to travel 477

lisov135 [29]

Answer:

212 pounds

Explanation:

477 nm / 180 nm/hr * 80 #/hr = 212 #

5 0

2 years ago

Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen

dsp73

Answer:

The spacing between the slits is $d = 0.00145m$

Explanation:

From the question we are told that

The wavelength of the light is $\lambda = 406.192nm = 406.192*10^{-9} m$

The distance of the slit from the screen is $D = 5.937 \ m$

The number of bright fringe is $n = 24$

The length the fringes span is $L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m$

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

$\beta = \frac{\lambda D}{d}$

Where d is the distance between the slits

$\beta$ is the fringe width which can also be evaluated as

$\beta = \frac{L}{n}$

Substituting values

$\beta = \frac{0.0398}{24}$

$\beta = 1.660 *10^{-3}$

Making d the subject of formula in the above equation

$d = \frac{\lambda D}{\beta }$

Substituting values

$d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}$

$d = 0.00145m$

4 0

4 years ago

I need a diagram for how a scrap heap magnet works

cupoosta [38]

Will this one work?...................

5 0

3 years ago

A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate

Stells [14]

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

∑ τ = 0

F l -x W = 0

F = $\frac{x}{l} \ W$

let's calculate

F = $\frac{4}{100}$ 4/100 600

F = 24 N

8 0

3 years ago

Q.4. What is the kinetic energy of a 10 kg car that is moving 4 m/s?

kodGreya [7K]

An object of mass $10 \mathrm{~kg}$ is moving with a uniform velocity of $4 \mathrm{~ms}^{-1}$ . The kinetic energy possessed by the object is $80 \mathrm{~J}$ .

Given:

Mass of an object $=10 \mathrm{~kg}$

Velocity $=4 \mathrm{~ms}^{-1}$

Kinetic Energy $=1 / 2 \times$ Mass of Object $\times(\text { Velocity })^{2}$

$\Rightarrow$ Kinetic Energy $=1 / 2 \times 10 \times 4 \times 4$

$\Rightarrow$ Kinetic Energy $=\underline{80 \mathbf{J}}$

What is Kinetic Energy?

In physics, an object's kinetic energy is the energy it has as a result of its motion.
It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.
The body retains its kinetic energy after gaining it during acceleration until its speed changes.
Kinetic energy is present in a speeding bullet, a walking human, and electromagnetic radiation such as light. The energy associated with the continual, random bouncing of atoms or molecules is another type of kinetic energy.

Learn more about kinetic energy brainly.com/question/12669551

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6 0

2 years ago