Coulomb's law:
Force = (<span>8.99×10⁹ N m² / C²<span>) · (charge₁) · (charge₂) / distance²
= (</span></span><span>8.99×10⁹ N m² / C²<span>) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C) / (1.0 m)²
= (8.99×10⁹ x 1×10⁻¹² / 1.0) N
= 8.99×10⁻³ N
= 0.00899 N repelling.
Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.
-- '4.0 kg masses'; don't need it.
Mass has no effect on the electric force between them.
-- 'frictionless table'; don't need it.
Friction has no effect on the force between them,
only on how they move in response to the force.
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1- You help others learn and train them ,2- it affects ur body in a good way which can help you when ur older ,3- if your at any near beach / pool and Somome is drowning u get them ,4- u can become a mermaid and get paid
I believe it’s c if not sorry
I would have to say that 'B' and 'D' are both correct.
Increasing the voltage that you're using to operate a circuit
causes the current in the circuit to increase. But current is
just the number of electrons that are flowing through it. So
right there, you have the increase in the number of charges.
Now, every electron that flows through the circuit gives up
some energy on the way. So if there are more electrons
making the trip, then more energy has been put into the circuit.
Jessica, I absolutely love your printing.
I wish I could print so clearly.
Answer:
The minimum velocity is V=5.98[m/s]
Explanation:
In this problem the athlete jumps by printing a force to raise his mass at an initial speed, which we must determine. These two initial amounts of energy that we have, the kinetic energy (velocity with which it jumps) and the work done (mass of the athlete by the jumped distance) must be equal to the kinetic energy when its velocity is equal to 0.65[m/s]. By raising this equation, the initial speed can be cleared.
We have to keep in mind that the weight is acting down and the movement is one up so the work done by the force is negative
Therefore we have:
Reorganizing each of the members of the equation and clearing the final velocity.