Answer:
<em>Velocity is the rate at which the position changes</em>
<em>Velocity is the rate at which the position changesWhy do we need</em>
<em>Velocity is the rate at which the position changesWhy do we needVectors make it convenient to handle quantities going in different directions</em><em>.</em><em>.</em><em> </em>
Explanation:
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The question is incomplete! The complete question along with answer and explanation is provided below.
Question:
A student bikes to school by traveling first 1.00 miles north, then 0.500 miles west and finally 0.200 miles south.
If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance db would the bird cover
Given Information:
distance towards north = dn = 1.00 mi
distance towards west = dw = 0.500 mi
distance towards south = ds = 0.200 mi
Required Information:
distance covered by bird = db = ?
Answer:
distance covered by bird = 0.94 miles
Explanation:
As you can see in the attached image, by applying the Pythagoras theorem,
db = √(dn - ds)² + dw²
db = √ (1.0 - 0.20)² + 0.50²
db = √ 0.80² + 0.50²
db = 0.94 miles
Therefore, the bird would cover a distance of 0.94 miles
False. They have a definite volume, but they take the shape of the container they are in.
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Answer and Explanation:
1. Evaluate the function x(t) at t=0.5
2. The period of motion T can be calculated as:
Where:
So:
3. The angular frequency can be expressed as:
Solving for k:
4. Find the derivate of x(t):
Now, the sine function reach its maximum value at π/2 so:
Solving for t:
Evaluating v(t) for 0.6603981634:
So the maximum speed of the block is:
In the negative direction of x-axis
5. The force is given by:
The cosine function reach its maximum value at 2π so:
Solving for t:
Evaluating x(t) for 3.016592654:
Therefore the the maximum force on the block is:
The wave takes 11.3 s to cover a distance of 26.5 m, so its speed is:
The distance between two consecutive crests is 3 m, and this corresponds to the wavelength of the wave. To find its frequency, we can use the relationship between the speed v, the wavelength
and the frequency f: