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Kobotan [32]
3 years ago
12

car 1 drives 45 mph to the west and car 2 drives 30mph to the east . from the frame of reference of car 1, what is the velocity

of car 2
Physics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

15 mph west

Explanation:

Velocity of car 1 with respect to ground, V1,o = 45 mph west

Velocity of car 2 with respect to car 1, V2,1 = 30 mph east

Take east direction as positive direction and west direction as negative direction.

By use of formula of relative velocity,

Velocity of car 2 with respect to car 1 is given by

V2, 1 = V2,o - V1,o

30 = V2,o - (-45)

V2,o = 30 - 45 = - 15 mph

It means the velocity of car 2 with respect to ground is 15 mph towards west.

Naya [18.7K]3 years ago
6 0
Distance between the two cars is increasing at the rate of 85 mph. 

A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.


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How many types Of Ornital does the atomic orbital have ?​
bixtya [17]

Answer:

There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals

3 0
3 years ago
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It requires 2,500 joules to raise a certain amount of water (c = 4.186 J/g C) from 20 C to 60 C
Ksivusya [100]

The mass of the water is 14.9 g

Explanation:

When a certain amount of a susbtance is heated, the temperature of the substance increases according to the equation

Q=mC_s \Delta T

where

Q is the amount of energy supplied to the substance

m is the mass of the substance

C_s is its specific heat capacity

\Delta T is the change in temperature

In this problem, we have:

Q = 2500 J of energy supplied to the water

C_s = 4.186 J/gC is the specific heat capacity of water

\Delta T=60 C - 20 C = 40^{\circ}C is the change in temperature of the water

Therefore we can solve for m to find the mass of the water:

m=\frac{Q}{C_s \Delta T}=\frac{2500}{(4.186)(40)}=14.9 g

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0
3 years ago
A Ferris wheel is a vertical, circular amusement ride with radius 6.0 m. Riders sit on seats that swivel to remain horizontal. T
Oksana_A [137]

Answer:

Incomplete question

The complete question is

A Ferris wheel is a vertical, circular amusement ride with radius 6.0 m. Riders sit on seats that swivel to remain horizontal. The Ferris wheel rotates at a constant rate, going around once in 9.6 s. Consider a rider whose mass is 96 kg.

At the bottom of the ride, what is the rate of change of the rider's momentum?

Explanation:

Radius of wheel is 6m

Rider mass=96kg

He completes one revolution in 9.6s

Let get angular velocity (w)

1 Revolution =2πrad

θ=2πrad

w= θ/t

w=2π/9.6

w=0.654rad/s

Linear speed is give as

v=wr

v=0.654×6

v=3.93m/s

Centripetal acceleration a

a=rw²

a=6×0.654²

a=2.57m/s²

Acceleration due to gravity g=9.81m/s²

According to Newton's second law of motion net force acting on the rider at the bottom of the ride is given by: the two force acting at the bottom is the normal and the weight of the rider

ΣF = ma

N-W=ma

N-mg=ma

N=ma+mg

N=m(a+g)

N=96(2.57+9.81)

N=1188.48 N

Therefore the rate of change of momentum at the bottom of the ride is 1188.48 N.

8 0
3 years ago
a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calc
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A. 0.5 miles an hour 
B. 0.2 miles an hour
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Two small space probes have been slowed to 10m/s as they approach the moon from the same direction. Probe 1 has a mass of 86kg a
bulgar [2K]

Answer:

B

Explanation:

B

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3 years ago
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