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Kobotan [32]
3 years ago
12

car 1 drives 45 mph to the west and car 2 drives 30mph to the east . from the frame of reference of car 1, what is the velocity

of car 2
Physics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

15 mph west

Explanation:

Velocity of car 1 with respect to ground, V1,o = 45 mph west

Velocity of car 2 with respect to car 1, V2,1 = 30 mph east

Take east direction as positive direction and west direction as negative direction.

By use of formula of relative velocity,

Velocity of car 2 with respect to car 1 is given by

V2, 1 = V2,o - V1,o

30 = V2,o - (-45)

V2,o = 30 - 45 = - 15 mph

It means the velocity of car 2 with respect to ground is 15 mph towards west.

Naya [18.7K]3 years ago
6 0
Distance between the two cars is increasing at the rate of 85 mph. 

A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.


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I believe it is b if i’m correct
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PLEASE HELP!!! WILL GIVE 30 POINTS!! HAS TO BE CORRECT!
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Explanation:

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4 0
2 years ago
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During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
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Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

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Now,

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a=\frac{v^2}{r}

r is the radius of the loop

on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

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5 0
3 years ago
A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
Read the description of the centrioles. What is their function?
KATRIN_1 [288]

Answer:

Typically found in eukaryotic cells, centrioles are cylindrical (tube-like) structures/organelles composed of microtubules. In the cell, centrioles aid in cell division by facilitating the separation of chromosomes. For this reason, they are located near the nucleus.

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