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Kobotan [32]
3 years ago
12

car 1 drives 45 mph to the west and car 2 drives 30mph to the east . from the frame of reference of car 1, what is the velocity

of car 2
Physics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

15 mph west

Explanation:

Velocity of car 1 with respect to ground, V1,o = 45 mph west

Velocity of car 2 with respect to car 1, V2,1 = 30 mph east

Take east direction as positive direction and west direction as negative direction.

By use of formula of relative velocity,

Velocity of car 2 with respect to car 1 is given by

V2, 1 = V2,o - V1,o

30 = V2,o - (-45)

V2,o = 30 - 45 = - 15 mph

It means the velocity of car 2 with respect to ground is 15 mph towards west.

Naya [18.7K]3 years ago
6 0
Distance between the two cars is increasing at the rate of 85 mph. 

A passenger in Car-1 says that he is at rest in his own frame of reference,
and Car-2 is moving away from him at 85 mph, toward the west.


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3 years ago
A(n) _________________ is a push or pull that one object exerts on another
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Explanation

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Red clothes will---the red light.A)Reflect B)refract C)Absorb D)transmission E)Dispersion
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Red clothes look red  because they REFLECT the red light, and absorb light of other colors.

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3 years ago
Two long, parallel wires carry currents of different magnitudes. If the amount of current in one of the wires is doubled, what h
Ulleksa [173]

Answer:

The magnitude of the force that each wire exerts on the other will increase by a factor of two.

Explanation:

force on parallel current carrying wire, F = BILsinθ

where;

B is the strength of the magnetic field

L is the length of the wire

I is the magnitude of current on the wire

θ is the angle of inclination of the wire

Assuming B, L and θ is constant, then F ∝ I

F = kI

\frac{F_1}{I_1} = \frac{F_2}{I_2}

When the amount of current is doubled in one of the wires, lets say the second wire;

\frac{F_1}{I_1} = \frac{F_2}{2I_1} \\\\F_2 = \frac{2F_1I_1}{I_1} \\\\F_2 =2F_1

Also, if will double the amount of current on the first wire, then

F₁ = 2F₂

Therefore, the magnitude of the force that each wire exerts on the other will increase by a factor of two.

3 0
4 years ago
A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.
Ugo [173]

Answer:

(A) 10052.2 m/s²

(B)  0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the  equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds

5 0
3 years ago
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