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4 years ago

Systems distribute heat energy by the circulation of air.

Physics

2 answers:

Fittoniya [83]4 years ago

7 0

The answer to this question is convection

Ulleksa [173]4 years ago

6 0

That seems like a statement more than a question. Where's the question?

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Lightbulb A is marked "25 W 120V, "and lightbulb B is marked "100 W 120V " These labels mean that each lightbulb has its respect

Dovator [93]

The cost of running the lightbulb A for 30 days at 0.110 per KWh is 1.98

<h3>How to determine the energy </h3>

We'll beging by calculating the energy used by lightbulb A. This can be obtained as follow:

Power (P) = 25 watts = 25 / 1000 = 0.025 KW
Time (t) = 30 days = 30 × 24 = 720 h
Energy (E) =?

E = Pt

E = 0.025 × 720

E = 18 KWh

<h3>How to determine the cost for running the bulb for 30 days</h3>

The cost of running the bulb for 30 days can be obtained as follow:

Cost per KWh = 0.11
Energy (E) = 18 KWh
Cost =?

Cost = energy × Cost per KWh

Cost = 18 × 0.11

Cost = 1.98

Lean more about buying electrical energy:

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3 0

2 years ago

The free fall motion shown in the<br>image must be

tatiyna

Answer:

Kinetic Energy?

Explanation:

3 0

3 years ago

An egg suspended above the ground has 93.1 J of gravitational potential energy. The egg is then dropped and falls to the ground.

Marina86 [1]

93.1 J of kinetic energy

3 0

3 years ago

In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu

tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

$294.3sin\theta = 20$

$sin\theta = 20/294.3 = 0.068$

$\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0$

So the ramp cannot be larger than 3.9 degrees

6 0

3 years ago

The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert

zimovet [89]

Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

$F=\dfrac{mv^2}{r}$

v is the maximum speed

$v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{15\times 0.8}{0.35}} \\\\v=5.86\ m/s$

Hence, the maximum speed of the ball is 5.86 m/s.

3 0

3 years ago