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noname [10]
3 years ago
13

The two strength factors that relate to all three competitive forces are

Physics
1 answer:
notka56 [123]3 years ago
7 0
I believe your answer is: Switching Costs & Customer Loyalty
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The speed of sound through diamond is about 12,000 m/s. The speed of sound through wood is about 3,300 m/s. Which statement expl
iris [78.8K]

Answer: They have different rigidities.

Explanation:

3 0
3 years ago
What is the force of gravity acting on a 1-kg m mass? (g = 9.8 m/s ^ 2)
Ksenya-84 [330]

Answer: Use this F=Ma.

Explanation: So your answer will be

F=1 Kg+9.8 ms-2

So the answer will be

F=9.8N

How'd I do this?

I just used Newton's second law of motion.

I'll also put the derivation just in case.

Applied force α (Not its alpha, proportionality symbol) change in momentum

Δp α p final- p initial

Δp α mv-mu (v=final velocity, u=initial velocity and p=v*m)

or then

F α m(v-u)/t

So, as we know v=final velocity & u= initial velocity and v-u/t =a.

So F α ma, we now remove the proportionality symbol so we'll add a proportionality constant to make the RHS & LHS equal.

So, F=<em>k</em>ma (where k is the proportionality constant)

<em>k</em> is 1 so you can ignore it.

So, our equation becomes F=ma

7 0
3 years ago
) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.7 × 10-3 m/s2, what is the gravitatonal
Sedbober [7]

Answer:

G = 6,786 10⁻¹¹ m³ / s² kg

Explanation:

The law of universal gravitation is

         F = G m M/ r²

Where G is the gravitational constant, m and M are the masses of the bodies and r is the distance from their centers

Let's use Newton's second law

         F = m a

The acceleration is centripetal

          a = a_{c}  

We replace

         G m M / r² = m  a_{c}  

         G =  a_{c}   r² / M

Let's replace and calculate

         G = 2.7 10⁻³ (3.88 10⁸)² / 5.99 10²⁴

         G = 6,786 10⁻¹¹ m³ / s² kg

Let's perform a dimensional analysis

[N m²/kg²] = [kg m/s²   m² / kg²] = [m³ / s² kg]

4 0
3 years ago
Heather drops a ball weighing 0.50kg a distance of 2.0m. If the speed of the ball right after it bounces is the same speed of th
ki77a [65]
The speed of the ball just before impact was v=√(2gh) = 6.26m/s.  The acceleration is twice this over the time (twice because the second speed is the same in the other direction, meaning the total change in speed is 2V)
a = 12.52/0.10 = 125.2m/s²
The force is F=ma, so F = 0.5kg·125.2m/s² = 62.6N
7 0
3 years ago
A battery supplies 0.75 A to three resistors connected in parallel. The current through the first resistor is 0.24 A and the cur
Anastasy [175]
Total current flow in circuit=0.75
Current flow through third resistor=0.75-(0.24+0.22)
=0.29
7 0
3 years ago
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