The two strength factors that relate to all three competitive forces are

Physics

1 answer:

notka56 [123]3 years ago

7 0

I believe your answer is: Switching Costs & Customer Loyalty

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Upper A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f

Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the wall.

The attached figure shows whole description such that,

$x^2+y^2=256$ .........(1)

$\dfrac{dx}{dt}=2\ ft/s$

We need to find, $\dfrac{dy}{dt}$ at x = 5 ft

Differentiating equation (1) wrt t as :

$2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0$

$2x+y\dfrac{dy}{dt}=0$

$\dfrac{dy}{dt}=-\dfrac{2x}{y}$

Since, $y=\sqrt{256-x^2}$

$\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}$

At x = 5 ft,

$\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}$

$\dfrac{dy}{dt}=0.65$

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0

3 years ago

The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an

yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

$\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}$