Answer:
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
Explanation:
The girl looks quite worried in the poster. Attached is the image:
A power source of 6.0 V is attached to the ends of a capacitor. The charge is 12 C.
2 answers:
The electric field at any point in the region between the conductors is proportional to the magnitude Q of charge on each conductor. It follows that:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:
Given that:
and 
Lastly, the capacitance is given by:
"The potential difference Vab between the conductors is also proportional to Q"
If we double the magnitude of charge on each conductor, the charge density at each point doubles, the electric field at each point doubles, and the potential difference between conductors doubles; however, the ratio of charge to potential difference does not change. This ratio is called the capacitance C of the capacitor:
Given that:
Lastly, the capacitance is given by:
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To solve this problem we will apply the concept given by the law of gravitational attraction, which properly defines gravity under the function
Here,
G = Gravitational Universal Constant
M = Mass of Earth
r = Distance between the human and the center of mass of the Earth
The acceleration due to gravity when is 4 times the mass of Earth and 3 times the radius would be given as,
The weight is defined as
So the new weight would be given as
Therefore the weight under this condition is 288.8N
(Missing figure is here: https://www.physicsforums.com/attachments/ch05-p070-jpg.149243/ )
Let's call
and 
the masses of the two blocks. We can write Newton's second law for both blocks (sum of all forces acting on the block = ma). On block 1, we have two forces: the weight 
pointing downwards and the tension of the string T poiting upwards. On block 2, we have the tension of the string going right and the friction 
going left. Therefore
Summing the two equations, we find
and then using
we can find the acceleration:
Let's call
Summing the two equations, we find
and then using