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3 years ago

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Clara played a video game before she left the house to go on a walk. She started with 0 points, lost 6 points 3 times, won 4 poi

nts and then lost 2 points. How many points did she have when she left the house to go on the walk?

1 answer:

s2008m [1.1K]3 years ago

6 0

She lost 16 points. Do -6×3, then add 2.

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PLD HELP ME IM STUCK

miv72 [106K]

Answer:

I think it's A: Similar - AA

Step-by-step explanation:

We know that ∠K≅∠N & ∠L≅∠P, so that gives us 2 sets of congruent angles

7 0

3 years ago

I need help with this i don’t understand

Phoenix [80]

Answer:

15

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7 0

3 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

Read 2 more answers

Find the solution to the system of equations x = -6 + 2y and x = 2y + 2.

andrew-mc [135]

x=-6+2y

x=2+2y

by subtraction

___________________________

x=-8

Substitute x by one of the two equations :

x=-6+2y

-8=-6+2y

2y=-8+6

2y=-2

y=-2/2

y=-1

I think this is the answer

I hope I helped you^_^

5 0

3 years ago

What is the equation of the line on the graph with points (-2,2) and (-2,-3)

nika2105 [10]

Answer:

x=-2

Step-by-step explanation:

Given points are (-2,2) and (-2,-3).

Now we need to find equation of the line passing through the given points.

So let's begin by finding slope

$m=\frac{\left(y_2-y_1\right)}{\left(x_2-x_1\right)}=\frac{\left(-3-2\right)}{\left(-2-\left(-2\right)\right)}=\frac{\left(-5\right)}{\left(-2+2\right)}=-\frac{5}{0}$

which is undefined. That means graph of the line must be vertical as you can see that in given points, x-value is not changing.

Equation of vertical line is given by x=k where k is the fixed value of x-coordinate.

x-coordinate is -2 in given points.

Hence final equation is x=-2.

4 0

3 years ago