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Nastasia [14]
3 years ago
14

A conducting bar slides without friction on two parallel horizontal rails that are 50 cm apart and connected by a wire at oneend

. The resistance of the bar and the rails is constant and equal to 0.10 Ω. A uniform magnetic field is perpendicular to theplane of the rails. A 0.080-N force parallel to the rails is required to keep the bar moving at a constant speed of 0.50 m/s. Whatis the magnitude of the magnetic field?
a. 0.36 Tb. 0.10 Tc. 0.54 Td. 0.93 Te. 0.25 T
Physics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

Explanation:

Given

Distance between rails d=50 cm

Resistance R=0.1 \Omega

Force F=0.08 N

velocity v=0.5 m/s

Magnetic Force is given

F=B\cdot I\cdot d\cdot \sin \theta

F=B*I*d*\sin 90

Also Emf is given by

e=B*d*v=I*R

I=\frac{B*d*v}{R}

thus

F=\frac{B^2*d^2*v}{R}

B=\sqrt{\frac{F*R}{d^2v}}

B=\sqrt{\frac{0.08*0.1}{0.5^2*0.5}}

B=0.25 T              

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