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NemiM [27]
3 years ago
10

A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it

exert on the track
Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

46620\ \text{N}

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Normal force at the point will be

N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}

The force exerted on the track is 46620\ \text{N}.

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<u>Option: D</u>

<u>Explanation:</u>

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Question 6. B) and c)
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4 0
4 years ago
What are the wavelength ranges for the following? (a) the AM radio band (540–1600 kHz) maximum wavelength m minimum wavelength m
Pie

Answer:

Explanation:

a ) AM radio band (540–1600 kHz)

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= 3 x 10⁸ / 1600 x 10³

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b )

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wave length = velocity of light / frequency

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wave length = velocity of light / frequency

= 3 x 10⁸ / 108 x 10⁶

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minimum wavelength =  2.78 m

3 0
3 years ago
select the correct scientific notation form of this numeral 541 5 * 10^2 5.4 * 10^2 5.4 * 10^2 5.0 * 10^2
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