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Nitella [24]
3 years ago
5

An object experiences an acceleration of 7.7 m/s^2. As a result, it accelerates from rest to 20 m/s. How much distance did it tr

avel during that acceleration?​
Physics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

Answer:

Answer:

pay back : the answer is 2 because 2 + 4 = 2

Step-by-step explanation:

2 + 4 = 2 your welcome

Explanation:

Explanation:

leonid [27]3 years ago
3 0

Answer:

26m

Explanation:

Given parameters:

Acceleration = 7.7m/s²

Initial velocity = 0m/s

Final velocity  = 20m/s

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the expression below:

      v²   = u²   + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

            20²  = 0²   +  (2 x 7.7 x S)

            400  = 15.4S

              S = 26m

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