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Hoochie [10]
3 years ago
8

I'll give you more points here is what I need.

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

We have hypothenuse which I will denote with h=6\sqrt{3} and angle \beta=30^{\circ}.

First we can use the sine function to determine the length of x by solving the following equality:

\sin(\beta)=\dfrac{x}{h}\implies x=\sin(\beta)h=\boxed{3\sqrt{3}}.

Simlarly, we can find y using cosine function:

\cos(\beta)=\dfrac{y}{h}\implies y=\cos(\beta)h=\boxed{9}.

Hope this helps.

Rus_ich [418]3 years ago
4 0

Answer:

x = 3sqrt(3)

y = 9

Step-by-step explanation:

x = 6sqrt(3)sin30

x = 3sqrt(3)

y = 6sqrt(3)cos30

y = 9

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Please solve it help me ..............<br>​
Sedbober [7]

Answer:

(a) = iv

b = i

c= ii

d = iii

Q-3

- radical 3

Step-by-step explanation:

8 0
3 years ago
Can someone explain how to solve this and the solution? Please and thank you :)
Verizon [17]
25 > 2x + 8 - 66

first simplify all numbers

25 > 2x + (8  - 66)
25 > 2x - 58

Then add 58 to both sides

25 (+58) > 2x - 58 (+58)
83 > 2x

Finally divide 2 from both sides to isolate the x

83/2 > 2x/2

41.5 > x

hope this helps
3 0
3 years ago
(02.04 LC)
Georgia [21]

Answer:

x = - 1

Step-by-step explanation:

the equation of a vertical line is

x = c

where c is the value of the x- coordinates the line passes through

the line passes through the x- intercept of - 1 , then

x = - 1 ← equation of vertical line

7 0
2 years ago
Ill give u brainliest pls help
Alenkinab [10]

Answer:

It is answer A) 5x^8y^8z^3 (sq rt 2y)

Step-by-step explanation:

1. Factor out the perfect square

(sqr rt) 5^2 × 2x^16 × y^16 xyz^6

2. Split each factor to their own square root

3. Simplify these roots

4 0
3 years ago
Read 2 more answers
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
3 years ago
Read 2 more answers
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