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FromTheMoon [43]
3 years ago
10

Calculate a vector c in the same direction of the vector a and that has the same length as the vector b

Mathematics
1 answer:
Viktor [21]3 years ago
8 0

For any scalar t>0, t\vec a is a vector pointing in the same direction as a.

To force this vector to have the same length as another vector \vec b, first normalize t\vec a by dividing it by its norm,

\dfrac{t\vec a}{\|t\vec a\|}=\dfrac{t\vec a}{t\|\vec a\|}=\dfrac{\vec a}{\|\vec a\|}

then multiply this vector by the norm of \vec b, so that

\vec c=\dfrac{\|\vec b\|}{\|\vec a\|}\vec a

To confirm that \vec c has the same length as \vec b:

\|\vec c\|=\left\|\dfrac{\|\vec b\|}{\|\vec a\|}\vec a\right\|=\dfrac{\|\vec b\|}{\|\vec a\|}\|\vec a\|=\|\vec b\|

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2 years ago
The graph represents function 1, and the equation represents function 2:
kvv77 [185]

Answer:

Please check the explanation.

Step-by-step explanation:

We know that the slope or rate of change of the function can be:

  • positive
  • negative
  • zero, or
  • undefined

Function 1

From the function 1 graph, it is clear that the graph is a horizontal line. We must note that the horizontal line has a slope or rate of change zero. The reason is that the horizontal line can not rise vertically. i.e. y₂-y₁=0

so using the slope formula

Rate of change = m = y₂-y₁ / x₂-x₁

Taking two points (x₁, y₁) = (0, 4), (x₂, x₁) = (1, 4)

Rate of change = m = 4-4 / 1-0

Rate of change = m = 0/1

Rate of change = m = 0

Thus, the rate of change of function 1 is zero.

Function 2

We know the slope-intercept form of linear equation is

y = mx+b

where m is the rate of change or slope of the function and b is the y-intercept

Given the function

y = 8x+12

comparing with the slope-intercept form i.e. y = mx+b

Therefore, the rate of change of function 2 = m = 8

Conclusion

The rate of change of function 1  = 0

The rate of change of function 2  = 8

as

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Therefore, function 2 has 8 more rate of change of function than the rate of change of function 1.

6 0
3 years ago
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