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zloy xaker [14]
4 years ago
6

What is the slope ? Please help

Mathematics
2 answers:
S_A_V [24]4 years ago
4 0

Answer:

y = -2/3x + 3    pic below to show proof     i hope this helps!   :)

Step-by-step explanation:

looking at the photo this slope is negative

we can see 2 given points   (0,3) and (3,1)

y = +/- ?/?x +/- ?

from the point (0,3) we move down 2

y = -2/? x + ?

from the point that was moved down 2, we move over 3 to get to (3,1)             y = -2/3x + ?

the line crosses the 3 on the y-axis

y = -2/3x + 3

lisov135 [29]4 years ago
3 0

Answer:

-2/3

Step-by-step explanation:

Okay, this is a fairly simple question.

First, you want to pick two pairs of coordinates (X,Y).

In this case, I chose (-3, 5) and (3, 1)

Now, you want to use the formula to find slope : y2-y1/x2-x1

1-5/3-(-3)

-4 divided by 6

=-2/3  

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Step-by-step explanation:

Find the gradient of the line that is perpendicular to the line 2y=3+5x

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The health of the bear population in a park is monitored by periodic measurements taken from anesthetized bears. A sample of the
Vikki [24]

Answer:

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

Step-by-step explanation:

Assuming the following dataset:

77, 349,417,349, 167 , 225, 265, 360,205

145,335,40,139, 177,108, 163, 202, 22

123,439, 125,135, 86,43, 217,49, 156

119,178, 151, 61, 350, 312, 91, 89,89

We can calculate the sample mean with the followinf formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}= 182.167

And the sample deviation with:

s = \sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}=114.05

The sample size on this case is n =36.

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=182.167 represent the sample mean  

\mu population mean (variable of interest)  

s=114.05 represent the sample standard deviation  

n=36 represent the sample size    

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The point estimate of the population mean is \hat \mu = \bar X =182.167

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=36-1=35  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,35)".And we see that t_{\alpha/2}=2.03  

Now we have everything in order to replace into formula (1):  

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

5 0
3 years ago
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