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Lerok [7]
3 years ago
15

Ollie is catering a dinner party for more than 26 guests. Each guest has a choice between a vegetarian dinner or a steak dinner.

The vegetarian dinner is $20 per plate and the steak dinner is $30 per plate. Ollie can spend no more than $690 on the entire party. If Ollie wants to purchase the most amount of food and still stay within budget, which combination of vegetarian and steak dinners is optimal?

Mathematics
1 answer:
Ratling [72]3 years ago
5 0
Using the graph that is included, look at the points given. For example (30, 3). There would be 30 vegetarian dishes and 3 steak dinners for a total of 33 meals. If that is plugged into the cost equation 20(30)+3(30) it would equal $690. The next point (33, 1) would cost 20(33) + 30(1) = $690 and but gives 34 meals. However, 34 vegetarian meals would only cost 20(34)=$680 and have 34 meals. 

If both types of meals need to be purchased, 33 vegetarians and 1 steak. If only vegetarians are purchased, the cost is cheaper by $10. 
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2 years ago
If cos A = k, then the value of the expression (sin A)(cos A)(tan A) is equivalent to:
sukhopar [10]

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1-k^2

Step-by-step explanation:

tan A= sin A/cos A

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2 years ago
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Simplify this answer <br><br> please help!
aliya0001 [1]

Answer:

(hope this helps can I pls have brainlist (crown) ☺️)

Step-by-step explanation:

7^8 x 7^3 x 7^4 / 7^9 7^5

= 7^(8+3+4) / 7^(9+5)

= 7^15 / 7^14

= 7^(15-14)

= 7.

When the bases of the numbers are the same when multiplying numbers with exponents, you can just add the exponents like so:

7^8 x 7^3 x 7^4= 7^15

Now, look at the rest of the simplified equation and do the same to the denominator:

 7^15 / 7^9 x 7^5 ⇒ 7^15/ 7^14

When the bases are the same in the fraction, you are allowed to subtract the exponents. This will lead you to the simplified answer  = 7^15-14 = 7^1  = 7

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3 years ago
Jack likes to go fishing. While waiting for the fishes to bite, he formulates the following model for the process: fishes bite a
gogolik [260]

Answer:

a) 0.122

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P(N(2) = 6) = \frac{e^{-4 \times 2} (4 \times 2)^6 }{6!} = 0.122

b) The probability that he fails to catch any fishes during the first two hours is the probability t that he catches 0 fish as follows

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4 0
3 years ago
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