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torisob [31]
3 years ago
13

In word form how do you write 710,718

Mathematics
2 answers:
tangare [24]3 years ago
8 0
710 = seven hundred and ten 
718 = seven hundred and eighteen :))
i hope this be helpful 
* happy new year * 
pickupchik [31]3 years ago
6 0
Seven hundred ten thousand and seven hundred eighteen

Hope I helped:)



















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Drupady [299]

Answer: The answer is Yes. A square is a rectangle because it possesses all the properties of a rectangle. These properties are: Interior angles measure 90∘ each.

Explanation:

Definition of a Rectangle:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, opposite sides are parallel and of equal length.

Definition of a Square:

A 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also, all sides have equal length

As you can see the first part of the definition of a square and rectangle are the same.

However, a square is a special case of a rectangle.

When all 4 sides of a rectangle are equal then the rectangle is a square.

So, a rectangle can also sometimes be a square.

 

Step-by-step explanation:

3 0
3 years ago
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iogann1982 [59]

Answer:

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3 0
3 years ago
The amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and standard deviation 13 mL. Supp
andreyandreev [35.5K]

Answer:

(a) X ~ N(\mu=63, \sigma^{2} = 13^{2}).

    \bar X ~ N(\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

Step-by-step explanation:

We are given that the amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and a standard deviation of 13 mL.

Suppose that 43 randomly selected people are observed pouring syrup on their pancakes.

(a) Let X = <u><em>amount of syrup that people put on their pancakes</em></u>

The z-score probability distribution for the normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean amount of syrup = 63 mL

            \sigma = standard deviation = 13 mL

So, the distribution of X ~ N(\mu=63, \sigma^{2} = 13^{2}).

Let \bar X = <u><em>sample mean amount of syrup that people put on their pancakes</em></u>

The z-score probability distribution for the sample mean is given by;

                      Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = mean amount of syrup = 63 mL

            \sigma = standard deviation = 13 mL

            n = sample of people = 43

So, the distribution of \bar X ~ N(\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < X < 62.8 mL)

   P(61.4 mL < X < 62.8 mL) = P(X < 62.8 mL) - P(X \leq 61.4 mL)

  P(X < 62.8 mL) = P( \frac{X-\mu}{\sigma} < \frac{62.8-63}{13} ) = P(Z < -0.02) = 1 - P(Z \leq 0.02)

                                                           = 1 - 0.50798 = 0.49202

  P(X \leq 61.4 mL) = P( \frac{X-\mu}{\sigma} \leq \frac{61.4-63}{13} ) = P(Z \leq -0.12) = 1 - P(Z < 0.12)

                                                           = 1 - 0.54776 = 0.45224

Therefore, P(61.4 mL < X < 62.8 mL) = 0.49202 - 0.45224 = 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < \bar X < 62.8 mL)

   P(61.4 mL < \bar X < 62.8 mL) = P(\bar X < 62.8 mL) - P(\bar X \leq 61.4 mL)

  P(\bar X < 62.8 mL) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{62.8-63}{\frac{13}{\sqrt{43} } } ) = P(Z < -0.10) = 1 - P(Z \leq 0.10)

                                                           = 1 - 0.53983 = 0.46017

  P(\bar X \leq 61.4 mL) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{61.4-63}{\frac{13}{\sqrt{43} } } ) = P(Z \leq -0.81) = 1 - P(Z < 0.81)

                                                           = 1 - 0.79103 = 0.20897

Therefore, P(61.4 mL < X < 62.8 mL) = 0.46017 - 0.20897 = 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

4 0
3 years ago
Eje cartesiano y=-x+7<br> 2
victus00 [196]

Answer:

45

Step-by-step explanation:

*jjjjjjbjjjjjjjjjjjjjjjjjjjjjjjnnnnn

8 0
3 years ago
You have a jar of Marbles in front of you 2 are Cordovan, 9 are yellow, 3 are white and 7 are red. What is the probability, as a
liubo4ka [24]

Answer:

2/35

Step-by-step explanation:

Assuming that this is without replacement,

The total amount of marbles is 2+9+3+7, or 21.

9 are yellow, 3 are white. this makes 12.

The probability of selecting a white or yellow marble is 12/21.

Now without replacement (comment if it is with replacement.), there are 20 marbles left, and 2 are Cordovan. This means there is a 2/20 chance then of picking a Cordovan marble.

After multiplying the fractions we get

(12/21) * (2/20) = 2/35.

There is a 2/35 chance of selecting a yellow or white, then a cordovan marble.

4 0
3 years ago
Read 2 more answers
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