1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Len [333]
3 years ago
9

You are an industrial engineer with a shipping company. As part of the package- handling system, a small box with mass 1.60 kg i

s placed against a light spring that is compressed 0.280 m. The spring has force constant 48.0 N/m . The spring and box are released from rest, and the box travels along a horizontal surface for which the coefficient of kinetic friction with the box is μk = 0.300. When the box has traveled 0.280 m and the spring has reached its equilibrium length, the box loses contact with the spring. (a) What is the speed of the box at the instant when it leaves the spring? (b) What is the maximum speed of the box during its motion?
Physics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

a) V = 0.82m/s

b) Vmax = 0.985 m/s

Explanation:

By conservation of energy we know that:

Eo = Ef    \frac{m*V^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*Xmax

Solving for V we get:

V = 0.82 m/s

To find the maximum speed we will do the same to an intermediate point where the compression is X and the distance for the work donde by frictions is given by (Xmax - X) = (0.28m - X):

\frac{m*Vmax^{2}}{2}+\frac{K*X^{2}}{2}-\frac{K*Xmax^{2}}{2}=-Ff*(Xmax-X)

Then we have to solve for V, derive and equal zero in order to find position X. After solving the derivative we get:

X = 0.1m    Replacing this value into the equation for Vmax:

Vmax = 0.985m/s

You might be interested in
A school bus transporting students to school is an example of
jok3333 [9.3K]

Answer:

The answer is D. If I got this right will you please mark me as Brainliest.

3 0
3 years ago
Read 2 more answers
A simple harmonic oscillator has an amplitude of 3. 50 cm and a maximum speed of 26. 0 cm/s. What is its speed when the displace
Marianna [84]

Answer:

1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?

Explanation:

3 0
1 year ago
What is Aristotle famous for?
Mila [183]

Answer:

History

Explanation:

Im. Sorry. Im. Not. Much. Help

8 0
3 years ago
You are pushing on a heavy desk with a force of 65 N the desk does not slide the force of friction between the desk and the floo
astra-53 [7]

When an object does not move even on pushing , static frictional force acts on in opposite direction of the applied force to stop the object from moving. static frictional force is a self adjusting force and it adjust its value according to the applied force if the applied force is smaller than the maximum value of static frictional force. The object starts moving once the applied force on it becomes greater than the maximum static frictional force.  hence the statement is true.

7 0
3 years ago
The two masses in the Atwood's machine shown in the figure are initially at rest at the same height. After they are released, th
Inga [223]

According to the description given in the photo, the attached figure represents the problem graphically for the Atwood machine.

To solve this problem we must apply the concept related to the conservation of energy theorem.

PART A ) For energy conservation the initial kinetic and potential energy will be the same as the final kinetic and potential energy, so

E_i = E_f

0 = \frac{1}{2} (m_1+m_2)v_f^2-m_2gh+m_1gh

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

PART B) Replacing the values given as,

h= 1.7m\\m_1 = 3.5kg\\m_2 = 4.3kg \\g = 9.8m/s^2 \\

v_f = \sqrt{2gh(\frac{m_2-m_1}{m_1+m_2})}

v_f = \sqrt{2(9.8)(1.7)(\frac{4.3-3.5}{3.5+4.3})}

v_f = 1.8486m/s

Therefore the speed of the masses would be 1.8486m/s

6 0
3 years ago
Other questions:
  • Which element in Figure 2 is a transition metal? Which is a noble gas?
    6·1 answer
  • What is the dot product of a= -2i - 5j and b=i -4j
    15·1 answer
  • A flashlight bulb is connected to a dry cell of voltage 2.25 V. It draws 35.0 mA (1000 mA = 1 A). What is its resistance?
    5·1 answer
  • Can someone help with these?
    13·1 answer
  • (a) It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80×107J of energy whe
    10·2 answers
  • If a velocity is positive which would most likely yield a negative acceleration
    5·1 answer
  • A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m
    6·1 answer
  • What are the five basic postulates of kinetic-molecular theory?
    12·1 answer
  • Which best explains why water boils in a pot sitting over fire?
    10·2 answers
  • You've always wondered about the acceleration of the elevators in the 101 story-tall Empire State Building. One day, while visit
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!