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2 years ago

How changes in solar position influence the intensity of radiation on a horizontal surface?

1 answer:

8 0

Changes in solar position influence the intensity of radiation on a horizontal surface because Energy concentration is greatly affected by changes in solar position. Energy intensity is greater when solar position is high. This concentrates more energy per unit area.

What determines the intensity of solar radiation?

The angle of the sun determines solar irradiance. The greater the angle, the lower the solar intensity. The lower the angle of the sun, the larger amount of ozone the light has to pass through.

What affects the intensity of solar energy?

The main parameters affecting the intensity of solar radiation are the zenith angle zeta of the sun, the water vapor content w of the atmosphere, and Schupp's turbidity coefficient B.

To learn more about solar radiation here

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In science, Bob learns that the energy of a wave is directly proportional to the square of the waves amplitude. If the energy of

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Answer:

Probably none of the above. it's says directly proportional so there would be a proportionality constant.

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4 years ago

According to the Big Bang Theory, the density and temperature of the Universe is ___________ now than in the past.

34kurt

Answer:

According to the Big Bang Theory, the density and temperature of the Universe is lower now than in the past.

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3 years ago

Which of the following expenses will most likely be the most expensive?

Jlenok [28]

Option B makes the most sense. Option A is something you acquire, it wouldn't really cost anything. Utilities usually do not cost more than housing. Savings are subjective, dependent on the person. So option B.
Hope it helps!

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3 years ago

For the winter, a duck flies 10.0 m/s due south against a gust of wind with a speed of 2.5 m/s. What is the resultant velocity o

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10.0 m/s + (-2.5 m/s) = 7.5 m/s

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4 years ago

An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them

Alexandra [31]

Answer:

1 / i + 1 / o = 1 / f thin lens equations

i = o f / (o - f) rearranging

Lens 1: object = 30 cm f = 15.2 cm

i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm

o2 = 40.2 - 30/8 = 9.4 cm distance of image 1 from lens 2

i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm

The final image is 24.6 cm to the left of lens 2

The first image is inverted

The second image is erect (as seen from the first image)

So the final image is inverted

M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69

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3 years ago